B because it’s the only one that doesn’t double in value
When the number expression given as (2tens 1 one) x 10 is written in standard form, the standard form is 210 and the unit form is 2 hundred, and 1 ten
<h3>How to write the number in standard form?</h3>
The number expression is given as:
(2tens 1 one) x 10
2 tens is represented as:
2 * 10
1 one is represented as:
1 * 1
So, the number expression can be rewritten as:
(2tens 1 one) x 10 = (2 * 10 + 1 * 1) x 10
Evaluate the product
(2tens 1 one) x 10 = (20 + 1) x 10
Evaluate the sum
(2tens 1 one) x 10 = (21) x 10
Evaluate the product
(2tens 1 one) x 10 = 210
When the number expression given as (2tens 1 one) x 10 is written in standard form, the standard form is 210 and the unit form is 2 hundred, and 1 ten
Using the above steps as a guide, we have:
- (5 hundreds 5 tens) * 10 ⇒ 5 thousands and 5 hundreds ⇒ 5500
- (2 thousands 7 tens) / 10 ⇒ 2 hundreds and 7 units ⇒ 207
- (4 ten thousands 8 hundred) / 10 ⇒ 4 thousands and 8 tens ⇒ 4080
Read more about standard form at
brainly.com/question/19169731
#SPJ1
Answer:
See below:
Step-by-step explanation:
Hello! I hope you are having a nice day.
We can solve this equation in a single step, we just need a bit of theory and a graph.
We can first see that its in
form. Which is also known as Slope-Intercept form.
This means that we know the following.
is the y coordinate of the y intercept.
is the slope of the line.
Since we know that, we can see that from our equation that the slope of the line is 3 and the y intercept is (0,-7).
Now that we've gotten that, we can start graphing.
The y intercept is -7 so we can plot (0,-7) as one of our points.
The slope of 3 means that we got up 3 units then right a single unit.
Therefore, another point could be (1,-4).
With our two points, we can create our graph by creating a straight line through those two points and therefore plotting our line.
Cheers!
Answer:
-4sinθcosθ
Step-by-step explanation:
Note:
1. (a + b)^2 = a^2 + 2ab + b^2
2. (a - b)^2 = a^2 - 2ab + b^2
3. sin^2θ + cos^2θ = 1
(sinθ -cosθ)^2 - (sinθ + cosθ)^2
= sin^2θ - 2sinθcosθ + cos^2θ - (sin^2θ + 2sinθcosθ + cos^2θ)
= sin^2θ + cos^2θ - 2sinθcosθ - (sin^2θ + cos^2θ + 2sinθcosθ)
= 1 - 2sinθcosθ - (1 + 2sinθcosθ)
= 1- 2sinθcosθ -1 - 2sinθcosθ
= - 2sinθcosθ - 2sinθcosθ
= -4sinθcosθ
Answer:
90
Step-by-step explanation: