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2 years ago

13

What is the apparent solution to this system of equations?

2 answers:

finlep [7]2 years ago

5 0

(3,2)
:):)
Hope this helps!!!!!

arlik [135]2 years ago

4 0

Answer:

x = (3,3)

Step-by-step explanation:

<em>This is going to be x = (3,3) because this is showing where the x, y stand. The x goes, ∧ and the y goes to the ⇒ SO this is going to be x = (3,3) because the x comes first before the 2!</em>

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What is the square root of y^3

tia_tia [17]

Answer:

$y^{\frac{3}{2}$

Step-by-step explanation:

Let $m=\sqrt{y^3}$

$m=(y^3)^{\frac{1}{2}}\\\\m=y^{3\times \frac{1}{2}}\ \ \ \ \ \ \ \ \ [as\ (x^a)^b=x^{ab}]\\\\m=y^{\frac{3}{2}$

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2 years ago

If m∠SRQ = 6x + 2 and m∠QRP = 2x + 10, find the value of x . *

Neko [114]

Answer:

for m∠SRQ x = 3

for m∠QRP x = 5

Step-by-step explanation:

1. 6x +2. 6 is being multiplied by a number so to find that number we do teh opposite

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7 0

2 years ago

what is the product in simplest form state any restrictions on the variable x+2/x-1/x+4/x^2+4*x-5

ValentinkaMS [17]

When it is simplified it is ( $\frac{(x+2)(x+5)}{x+4}$ )

1 or 5

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3 years ago

Which of the is not a function

Lina20 [59]

Answer:

c)

Step-by-step explanation:

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Hope this helps

5 0

2 years ago

et f(x) = x + |2x − 3|. Find all solutions to the equation f(x) = 12. (Enter your answers as a comma-separated list. If an answe

Alinara [238K]

Answer:

1. {5,-9}

2.{4}

3.{9/2}

Step-by-step explanation:

The equation $f(x)=x+\lvert 2x-3 \rvert=12$ can be solved as follows:

$x+\lvert 2x-3 \rvert =12\,\,\,\text{(given equation)}$

$\lvert 2x-3 \rvert =12-x$

$2x-3=12-x\,\,\text{or}\,\,2x-3=-(12-x)$

$3x=15\,\,\text{or}\,\,\x=-9$

Then, the solutions of the equation are $x=5, x=-9$ .

Now, if $g(x)=5x-3+\lvert x+4\rvert$ , we can solve the equation $g(a)=4a+9$ as follows:

$5a-3+\lvert a+4 \rvert =4a+9$

$\lvert a+4\rvert =4a+9-5a+3$

$a+4 =-a+12\,\,\text{or}\,\,a+4=-(-a+12)$

$2a=8\,\,\text{or}\,\,4=12$

So, the unique solution of this last equation is $a=4$

The last equation is $h(x-1)=x-3$ , where $h(x)=\lvert x \rvert -2x+5.$ . To solve this equation we can proceed as follows:

$h(x-1)=x-3$

$\lvert x-1\rvert -2(x-1)+5=x-3$

$\lvert x-1 \rvert -2x+2+5=x-3$

$\lvert x-1\rvert =3x-10$

$x-1=3x-10\,\,\text{or}\,\,x-1=-(3x-10)$

$-2x=-9\,\,\text{or}\,\,4x=11$

$x=9/2\,\,\text{or}\,\,x=11/4$

But, x=11/4 is not a solution of this equation. So the unique solution is x=9/2.

8 0

2 years ago