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xxTIMURxx [149]
3 years ago
6

You have a jar of marbles. There are 15 red, 20 blue, 7 green, and 18 yellow marbles. You choose a marble at random from the jar

. You then replace it and choose another one. What is the probability that both marbles are blue?
a: 1/3600 d: 1/10
b: 2/3 c:1/9 no explanation just answer
Mathematics
1 answer:
Nookie1986 [14]3 years ago
6 0

Answer:

the right answer is b. 2/3

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lozanna [386]
I think it's 37.5 . I'm pretty sure cause I think you divide 3/8 . Then you go 2 to the right for your answer with the decimal. Not sure but . I think I'm right.
7 0
3 years ago
What is the area of this figure?
irakobra [83]
40+25+25+70=160 Hope this helps! :)

6 0
3 years ago
Read 2 more answers
Please graph y= 1/2x–3<br> Please i need help with this &lt;3
erik [133]

Answer:

coordinates are 6, -3

Step-by-step explanation:

When it's plotted out onto a graph, the answer comes down to 6, -3 (also remember, it's X then Y)

6 0
3 years ago
The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra
Snezhnost [94]
Let X denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by X_1,\ldots,X_{36}, each independently and identically distributed with distribution X_i\sim\mathcal N(26,7.2).

You want to find

\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)

Recall that if X\sim\mathcal N(\mu,\sigma), then the sampling distribution \overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right) with n being the size of the sample.

Transforming to the standard normal distribution, you have

Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}

so that in this case,

Z=6\dfrac{\overline X-26}{7.2}

and the probability is equivalent to

\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)
=\mathbb P(Z>1.481)\approx0.0693
5 0
3 years ago
Please help me with questions 23, 24, and 25
alekssr [168]
Problem 23
A = 40
B = 3x+1
C = 3x+1
B and C are congruent, so they have the same angle measure

The three angles of any triangle add to 180 degrees
A+B+C = 180
40+(3x+1)+(3x+1) = 180
6x+42 = 180
6x = 180-42
6x = 138
x = 138/6
x = 23

Answer: B) 23

============================================================

Problem 24

AB is the midsegment parallel to XY
So AB is half that of XY
AB = (1/2)*XY
AB = (1/2)*28
AB = 14

Answer: B) 14

============================================================

Problem 25

Note the ratio of the given rectangle's sides: 7/12 = 0.583 roughly

Divide the answer choices in a similar fashion
A) 5/7 = 0.714
B) 14/36 = 0.389
C) 21/36 = 0.583
D) 21/48 = 0.4375

We get the same result in choice C as we did in the original rectangle

Answer: C) 21 ft x 36 ft

6 0
3 years ago
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