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2 years ago

Write the slope-intercept form of a linear equation given the slope and y-intercept. Slope : y – intercept: -3

Mathematics

1 answer:

Alexxx [7]2 years ago

7 0

Answer:

this question doesn't make sense you forgot a number

Step-by-step explanation:

yeet

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For the following exercises, find (f ∘ g)(x) and (g ∘ f)(x) for each pair of functions.

Rufina [12.5K]

Answer:

The value of $(f \circ g)(x)$ is 17-18x and $(g \circ f)(x)$ is -7-18x.

Step-by-step explanation:

It is given in the question functions f(x) as 3x+2 and g(x)=5-6x.

It is required to find $(f \circ g)(x)$ and $(g \circ f)(x)$ .

To find $(f \circ g)(x)$ , substitute g(x) for x in f(x) and simplify the expression.

To find $(g \circ f)(x)$ , substitute f(x) for x in g(x) and simplify the expression.

Step 1 of 2

Substitute g(x) for x in f(x) and simplify the expression.

$\begin{aligned}&(f \circ g)(x)=f(5-6 x) \\&(f \circ g)(x)=3(5-6 x)+2 \\&(f \circ g)(x)=15-18 x+2 \\&(f \circ g)(x)=17-18 x\end{aligned}$

Step 2 of 2

Substitute f(x) for x in g(x) and simplify the expression.

$\begin{aligned}&(g \circ f)(x)=g(3 x+2) \\&(g \circ f)(x)=5-6(3 x+2) \\&(g \circ f)(x)=5-18 x-12 \\&(g \circ f)(x)=-7-18 x\end{aligned}$

5 0

2 years ago

The major math strands for a sixth grade curriculum are number sense and operations, algebra, geometry and spatial sense, measur

Radda [10]

Answer:

i didn't learn algebra or geometry or spatial sense when i was in sixth grade

Step-by-step explanation:

3 0

3 years ago

Pleeeeese help me as fast as you can!!!

Aleonysh [2.5K]

Answer:

A. $y=3x-10$

C. $y+6=3(x-15)$

Step-by-step explanation:

Given:

The given line is $6x+18y=5$

Express this in slope-intercept form $y=mx+b$ , where m is the slope and b is the y-intercept.

$6x+18y=5\\18y=-6x+5\\y=-\frac{6}{18}x+\frac{5}{18}\\y=-\frac{1}{3}x+\frac{5}{18}$

Therefore, the slope of the line is $m=-\frac{1}{3}$ .

Now, for perpendicular lines, the product of their slopes is equal to -1.

Let us find the slopes of each lines.

Option A:

$y=3x-10$

On comparing with the slope-intercept form, we get slope as $m_{A}=3$ .

Now, $m\times m_{A}=-\frac{1}{3}\times 3=-1$ . So, option A is perpendicular to the given line.

Option B:

For lines of the form $x=a$ , where, a is a constant, the slope is undefined. So, option B is incorrect.

Option C:

On comparing with the slope-point form, we get slope as $m_{C}=3$ .

Now, $m\times m_{C}=-\frac{1}{3}\times 3=-1$ . So, option C is perpendicular to the given line.

Option D:

$3x+9y=8\\9y=-3x+8\\y=-\frac{3}{9}x+\frac{8}{9}\\y=-\frac{1}{3}x+\frac{8}{9}$

On comparing with the slope-intercept form, we get slope as $m_{D}=-\frac{1}{3}$ .

Now, $m\times m_{D}=-\frac{1}{3}\times -\frac{1}{3}=\frac{1}{9}$ . So, option D is not perpendicular to the given line.

8 0

3 years ago

If a = 8 and b = 15, then c<br> =

Anika [276]

Then c = 22 just keep adding 7
8+7=15 15+7=22

4 0

3 years ago

I just need the last 2 boxes. PLZ HELP

Vladimir79 [104]

Answer: first box: 1/8

second box: 4

Step-by-step explanation:

4 0

3 years ago

Write the slope-intercept form of a linear equation given the slope and y-intercept. Slope : y – intercept: -3​

Write the slope-intercept form of a linear equation given the slope and y-intercept. Slope : y – intercept: -3