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2 answers:
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Answer:
A) -sqrt(3)/3
Step-by-step explanation:
If you know your unit circle (attached), 11pi/6 has the value of (sqrt(3)/2,-1/2), where the coords are (cosine, sine).
Tangent is sine/cosine:
(-1/2)/(sqrt(3)/2)
We can convert this to multiplication by miltiplying the reciprocal of sqrt(3)/2:
(-1/2)*(2/sqrt(3))
Multiplied out to:
-2/(2sqrt(3))
We have to rationalize this by multiplying the numerator and denominator by sqrt(3):
-2(sqrt(3))/2sqrt(3)(sqrt(3)
two of the same square roots multiplied together equals the number without the sqrt:
-2(sqrt(3))/2*3
we can factor out 2 from the numerator and denominator:
-sqrt(3)/3
Therefore, the answer is A
The function f(x)=x²
The vertex of the f(x) is at (0,0)
The vertex of the g(x) is at (0+7;0+5)=(7;5)
x(p)=7, y(q)=5
The vertex form of a quadratic equation is y = a(x -p)² + q, where (p, q) are the x- and y-coordinates of the vertex:
The answer:
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The vertex of the f(x) is at (0,0)
The vertex of the g(x) is at (0+7;0+5)=(7;5)
x(p)=7, y(q)=5
The vertex form of a quadratic equation is y = a(x -p)² + q, where (p, q) are the x- and y-coordinates of the vertex:
The answer:
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