Please hurry! Marking beainliest!
2 answers:
You might be interested in
Step-by-step explanation:
If the parabola has the form
(vertex form)
then its vertex is located at the point (h, k). Therefore, the vertex of the parabola
is located at the point (8, 6).
To find the length of the parabola's latus rectum, we need to find its focal length <em>f</em>. Luckily, since our equation is in vertex form, we can easily find from the focus (or focal point) coordinate, which is
where is called the focal length or distance of the focus from the vertex. So from our equation, we can see that the focal length <em>f</em> is
By definition, the length of the latus rectum is four times the focal length so therefore, its value is
Answer:
a) No. t < 0 is not part of the useful domain of the function
b) 2.0 seconds
Step-by-step explanation:
a) A graph of the function is shown below. It shows t-intercepts at t=-0.25 and t=2.0. We presume that t is measured forward from some event such as the ball being thrown or hit. The model's predicted ball location has no meaning prior to that event, when values of t are negative.
__
b) It is convenient to use a graphing calculator to find the t-intercepts. Or, the equation can be solved for h=0 any of several ways algebraically. One is by factoring.
h = 0 = -16t² +28t +8 . . . . . . . . . . . . the ball hits the ground when h = 0
0 = -4(4t² -7t -2) = -4(4t +1)(t -2)
This has t-intercepts where the factors are zero, at t=-1/4 and t=2.
The ball will hit the ground after 2 seconds.
