Answer: 0.0793
Step-by-step explanation:
Let the IQ of the educated adults be X then;
Assume X follows a normal distribution with mean 118 and standard deviation of 20.
This is a sampling question with sample size, n =200
To find the probability that the sample mean IQ is greater than 120:
P(X > 120) = 1 - P(X < 120)
Standardize the mean IQ using the sampling formula : Z = (X - μ) / σ/sqrt n
Where; X = sample mean IQ; μ =population mean IQ; σ = population standard deviation and n = sample size
Therefore, P(X>120) = 1 - P(Z < (120 - 118)/20/sqrt 200)
= 1 - P(Z< 1.41)
The P(Z<1.41) can then be obtained from the Z tables and the value is 0.9207
Thus; P(X< 120) = 1 - 0.9207
= 0.0793
In each case divide the price by the number of cans.
The best buy is the lowest price.
$12.53/7 = $1.79
$5.97/3 = $1.99
$7.95/5 = $1.59
$8.34/6 = $1.39
The fourth ad, $8.34 for 6 cans results in the lowest price per can, $1.39.
The fourth ad is the best buy.
Answer:
7 miles
Step-by-step explanation:
Four miles plus 3 miles = 7 miles
% is a number over 100, so 40% is 40/100, which is 0.40.
60% decimal = .6 fraction= 6/10
3/4 percent =75% (think of $$) decimal =.75
0.23 percent =23% fraction= 23/100
1/8 percent= 12.5 decimal = 0.125
18% decimal= .18 fraction= 18/100 (simplified to 9/50)
2/3 percent=0.6% repeating (so put a line over 6) decimal= 0.6 repeating aswell so do the same as last
Your welcome :)
