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Aliun [14]
3 years ago
14

Find the volume of a cylinder either enter an exact number in the terms of pi areU3.14 for pie 5 and 2

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
3 0

Answer:

V=384\pi \ \text{unit}^3

Step-by-step explanation:

The attached figure shows a cylinder of radius 8 units and height 6 units. We need to find the volume of the cylinder. The formula is as follows :

V=\pi r^2h\\\\V=\pi (8)^2\times 6\\\\V=384\pi

So, the required volume of the cylinder is 384\pi \ \text{unit}^3.

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2 years ago
Standard form of a line passing through points (1, 3) and (-2, 5)
____ [38]

Answer:

<h2>2x + 3y = 33 </h2>

Step-by-step explanation:

As we move from (-2, 5) to (1, 3), x increases by 3 and y decreases by 2.

Hence, the slope of this line is m = rise / run = -2/3.

Start with the slope-intercept form y = mx + b.

Substitute 3 for y and 1 for x and -2/3 for m:

3 = (-2/3)(1) + b.

Remove fractions by mult. all three terms by 3:

9 = -2 + b, so b = 11, and y = (-2/3)x + 11

Again, mult. all three terms by 3:

3y = -2x + 33, or, in standard form,

<h2>2x + 3y = 33 </h2>
6 0
3 years ago
Tina earned $300. This amount represented 40% of the money she needed to pay for her senior trip. What is the cost of the senior
ludmilkaskok [199]

Answer:

she needed $480 to pay for her trip

7 0
3 years ago
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Step-by-step explanation:

5 0
2 years ago
Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species
kotegsom [21]

Answer:

P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}

Step-by-step explanation:

The logistic equation is the following one:

P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}

In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.

In this problem, we have that:

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that P(0) = 80, K = 2000.

The number of fish tripled in the first year. This means that P(1) = 3P(0) = 3(80) = 240.

Using the equation for P(1), that is, P(t) when t = 1, we find the value of r.

P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}

240 = \frac{2000*80e^{r}}{2000 + 80(e^{r} - 1)}

280*(2000 + 80(e^{r} - 1)) = 160000e^{r}

280*(2000 + 80e^{r} - 80) = 160000e^{r}

280*(1920 + 80e^{r}) = 160000e^{r}

537600 + 22400e^{r} = 160000e^{r}

137600e^{r} = 537600

e^{r} = \frac{537600}{137600}

e^{r} = 3.91

Applying ln to both sides.

\ln{e^{r}} = \ln{3.91}

r = 1.36

This means that the expression for the size of the population after t years is:

P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}

4 0
3 years ago
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