Relative to the graph of y=3sinx what is the shift of the graph of y=3sin(x+pi/3)

1 answer:

4 0

The shifts of the sinus function can be described with the formula:
asin(bx−c)+d, where
a is the amplitude
b is the period
c is the phase shift
d is the vertical shift
So, the graph y=3sinx is phase shifted. The phase shift can be calculated as c/b= pi/3/1=pi/3
So, the function is phase shifted for pi/3.

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Is this right pls...

Dmitry [639]

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raketka [301]

Answer:

$\text{1. } v=16t+\frac{h-c}{t},\\\text{2. }90\:\mathrm{ft/s}, \\\text{3. Cannot be determined}$

Step-by-step explanation:

1. The initial equation given to us is $h=-16t^2+vt+c$ . Rearranging the equation to isolate $v$ , we have:

$vt=16t^2+h-c,\\\boxed{v=16t+\frac{h-c}{t}}$

2. Using the equation we rearranged in part 1, we can substitute given values:

$v=16(3)+\frac{131-5}{3},\\v=48+42=\boxed{90\:\mathrm{ft/s}}$

3. We see from our equation in part 1 ( $v=16t+\frac{h-c}{t}$ ) that when $t=0$ , the denominator of our fraction will be equal to 0. Since we cannot divide by 0, the velocity remains undefined and cannot be determined.