Relative to the graph of y=3sinx what is the shift of the graph of y=3sin(x+pi/3)

1 answer:

4 0

The shifts of the sinus function can be described with the formula:
asin(bx−c)+d, where
a is the amplitude
b is the period
c is the phase shift
d is the vertical shift
So, the graph y=3sinx is phase shifted. The phase shift can be calculated as c/b= pi/3/1=pi/3
So, the function is phase shifted for pi/3.

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Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

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From the question the points are

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The distance is

$|AB| = \sqrt{ ({10 + 2})^{2} + ({ - 1 - 5})^{2} } \\ = \sqrt{ {12}^{2} + ({ - 6})^{2} } \\ = \sqrt{144 + 36} \: \: \: \: \: \: \: \\ = \sqrt{180} \\ = 6 \sqrt{5} \: \: \\ =13.416407$