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3 years ago

All Questions are fron percentage and its applications

Mathematics

1 answer:

Likurg_2 [28]3 years ago

7 0

Answer:

1.20%

Step-by-step explanation:

1.50-30=20

2.15000

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A sales person is given a choice of two salary plans. Plan 1 is a weekly salary of 700 plus 4% commission of sales. Plan 2 is a

bezimeni [28]

Let 's' represent the amount of sales.

Plan 1:

$\text{ \$700 + (4\% of s)}$ $\begin{gathered} \text{ \$700+(}\frac{\text{4}}{100}\times s) \\ \text{ \$700+(0.04}\times s)=\text{ \$700}+0.04s \end{gathered}$

Plan 2:

$12\text{ \% of s}$ $\begin{gathered} \frac{12}{100}\times s \\ 0.12\times s=0.12s \end{gathered}$

Equating the two plans together and solving for the amount of sales,

$\begin{gathered} \text{Plan 2=Plan 1} \\ 0.12s=\text{ \$700+0.04s} \\ \end{gathered}$

Collecting like terms,

$\begin{gathered} 0.12s-0.04s=\text{ \$700} \\ 0.08s=\text{\$700} \end{gathered}$

Divide both sides by 0.08,

$\begin{gathered} \frac{0.08s}{0.08}=\frac{\text{ \$700}}{0.08} \\ s=\text{ \$8750} \end{gathered}$

Hence, the amount of sales is $8,750.

6 0

1 year ago

Solve the right triangle. round your answer to the nearest tenth

mrs_skeptik [129]

Answer:

Step-by-step explanation:

4 0

3 years ago

F(x)=|x+8| evaluate f(-11)

stealth61 [152]

19:)
I hope that helped!

7 0

3 years ago

I’m not sure about this question can someone help me.

Alisiya [41]

Step-by-step explanation:

$tan \: 48 \degree = \frac{x}{61} \\ \\ 1.11 = \frac{x}{61} \\ \\ x = 1.11 \times 61 \\\\ x = 67.7 feet\:$

RP = 67.7 feet

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3 years ago

Solving separable differential equation DY over DX equals xy+3x-y-3/xy-2x+4y-8

Ivanshal [37]

It looks like the differential equation is

$\dfrac{dy}{dx} = \dfrac{xy + 3x - y - 3}{xy - 2x + 4y - 8}$

Factorize the right side by grouping.

$xy + 3x - y - 3 = x (y + 3) - (y + 3) = (x - 1) (y + 3)$

$xy - 2x + 4y - 8 = x (y - 2) + 4 (y - 2) = (x + 4) (y - 2)$

Now we can separate variables as

$\dfrac{dy}{dx} = \dfrac{(x-1)(y+3)}{(x+4)(y-2)} \implies \dfrac{y-2}{y+3} \, dy = \dfrac{x-1}{x+4} \, dx$

Integrate both sides.

$\displaystyle \int \frac{y-2}{y+3} \, dy = \int \frac{x-1}{x+4} \, dx$

$\displaystyle \int \left(1 - \frac5{y+3}\right) \, dy = \int \left(1 - \frac5{x + 4}\right) \, dx$

$\implies \boxed{y - 5 \ln|y + 3| = x - 5 \ln|x + 4| + C}$

You could go on to solve for $y$ explicitly as a function of $x$ , but that involves a special function called the "product logarithm" or "Lambert W" function, which is probably beyond your scope.

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2 years ago