Answer:
3
Step-by-step explanation:
Calculate the distance d using the distance formula
d = 
with (x₁, y₁ ) = (5, 4) and (x₂, y₂ ) = (- 1, 1)
d = 
= 
= 
= 
= 3 ← exact value
≈ 6.71 ( to 2 dec. places )
Answer:
Hard questions
Step-by-step explanation:
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
15x = 3x + 120 (subtract both sides by 3x)
12x = 120 (divide both sides by 12)
x = 100
7(3x/1)=-1
7(3x)=-1
21x=-1
21x/21=-1/21
X=-1/21
Answer: -1/21
