For this case we have the following expression:
(x ^ 2 + 2x + 1 / x ^ 2-8x + 16) / (x + 1 / x ^ 2-16)
Rewriting we have:
(((x + 1) (x + 1)) / ((x-4) (x-4))) / (x + 1 / ((x + 4) (x-4)))
Then, we cancel similar terms:
((x + 1) / (x-4)) / (1 / (x + 4))
Rewriting:
((x + 1) (x + 4)) / (x-4)
Answer:
((x + 1) (x + 4)) / (x-4)
Answer:
infinite solutions
Step-by-step explanation:
2x-6 = 3x+1-X-7
Combine like terms
2x-6 = 3x-x +1-7
2x-6 = 2x -6
subtract 2x from each side
-6 = -6
Since this is a true statement, x can be any real number
