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Anika [276]
3 years ago
13

ANSWER AND EXPLAIN I’LL MARK BRAINLIEST GIVING 26 POINTS

Mathematics
1 answer:
Anettt [7]3 years ago
3 0

Answer:

Estimate (eye-ballin'): around (3, 3)

Calculation: (2.6, 3.2)

Step-by-step explanation:

<u>Given:</u>

4x + 3y = 20

y = 2x - 2

<u>Sophia's strat is absolutely correct. She makes two equations into one. This is called "substitution":</u>

- Insert <em>y</em> of 2nd equation as <em>y</em> in 1st equation:

4x + 3(2x - 2) = 20

<em>**Remember to multiply the entire thing by 3**</em>

4x + 6x - 6 = 20

<em>**Solve for x**</em>

10x - 6 = 20

10x = 26

x = 2.6

<u>Now that we have </u><u><em>x</em></u><u>, just plug it into any equation to find </u><em><u>y </u></em><u>(hint 2nd is easier):</u>

y = 2(2.6) - 2

y = 3.2

COORDS: (2.6, 3.2)

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6.833 + 3.594 + 1.369 nearest whole number
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Read 2 more answers
Suppose theta is an angle in the standard position whose terminal side is in quadrant 4 and cot theta = -6/7. find the exact val
zimovet [89]

First off, let's notice that the angle is in the IV Quadrant, where sine is negative and the cosine is positive, likewise the opposite and adjacent angles respectively.

Also let's bear in mind that the hypotenuse is never negative, since it's simply just a radius unit.

\bf cot(\theta )=\cfrac{\stackrel{adjacent}{6}}{\stackrel{opposite}{-7}}\qquad \impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{6^2+(-7)^2}\implies c=\sqrt{36+49}\implies c=\sqrt{85} \\\\[-0.35em] ~\dotfill

\bf tan(\theta)=\cfrac{\stackrel{opposite}{-7}}{\stackrel{adjacent}{6}} ~\hfill csc(\theta)=\cfrac{\stackrel{hypotenuse}{\sqrt{85}}}{\stackrel{opposite}{-7}} ~\hfill sec(\theta)=\cfrac{\stackrel{hypotenuse}{\sqrt{85}}}{\stackrel{adjacent}{6}} \\\\\\ sin(\theta)=\cfrac{\stackrel{opposite}{-7}}{\stackrel{hypotenuse}{\sqrt{85}}}\implies \stackrel{\textit{and rationalizing the denominator}}{sin(\theta)=\cfrac{-7}{\sqrt{85}}\cdot \cfrac{\sqrt{85}}{\sqrt{85}}\implies sin(\theta)=-\cfrac{7\sqrt{85}}{85}}

\bf cos(\theta)=\cfrac{\stackrel{adjacent}{6}}{\stackrel{hypotenuse}{\sqrt{85}}}\implies \stackrel{\textit{and rationalizing the denominator}}{cos(\theta)=\cfrac{6}{\sqrt{85}}\cdot \cfrac{\sqrt{85}}{\sqrt{85}}\implies cos(\theta)=\cfrac{6\sqrt{85}}{85}}

6 0
3 years ago
Please help its due tomorrow ​
Xelga [282]

Answer:

Area of triangle formula:

A = b*h/2

B is 18 and h is 13

B is base and h is height.

18 * 13 is 234.

We must divide by two because just multiplying the two numbers would result in an area of a square, divide by 2 for a triangle.

234/2 =

117 km²

3 0
3 years ago
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