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3 years ago

Helpp

Mathematics

1 answer:

JulsSmile [24]3 years ago

8 0

1. The independent variable is the height that the plant grows
2.The dependent variable is the days. The range is Monday-sat aka 7.
3. As the week goes by the plant grows approximately 5mm.

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vova2212 [387]

Answer: Because we are trying to find the x-intercepts and the y-intercepts That would be (C)

Step-by-step explanation:

Self explanatory question, you set a quadratic equation to zero

For example: x 2 – 6 x = 16 equals to x 2 – 6 x – 16 = 0

Then, you would factor, that equals to (x – 8)( x + 2) = 0

(X-8)=0 (X+2)=0

X+2=0

-2 =-2

X=-2

X-8=0

+8 =+8

X=-8

To check you would simply plug in the values into the quadratic equation. They would both equal 16=16

:) Multiple choices are difficult but the best answers are C or D GO WITH YOUR GUT!

3 0

4 years ago

Factor x^4 - 2x^3 - 33x^2 + 50x + 200 completely using the given factor x^2 - 25.

PIT_PIT [208]

You can do synthetic division twice immediately (or once if you know how to handle x^2 - 25 all at once. I'll use 2 divisions. x^2 - 25 is (x + 5)(x - 5). Both of them are zeros to the given equation which means that x = +5 and

x = - 5 are both zeros of the given quartic.

5 1 -2 -33 50 200

5 15 -90 -200

=====================================

1 3 -18 -40 0

What you have now is x^3 + 3x^2 - 18x - 40 = 0

Do another synthetic division

-5 1 3 -18 -40

-5 10 40

============================

1 -2 -8 0

The result is

x^2 - 2x - 8 = 0 which factors.

(x + 2)(x - 4) = 0

Answer

The factors are (x + 2)(x - 4)(x + 5)(x - 5) = 0

Long division

x^2 + 0 + 25 ||x^4 - 2x^3 - 33x^2 + 50x + 200 ||x^2 - 2x - 8

x^4 + 0 + 25x^2

==================

-2x^3 -8x^2 + 50x

-2x^3 + 0 + 50x

=================

-8x^2 + 0 +200

-8x^2 + 0 + 200

==================

5 0

4 years ago

PLEASE HELP!!!

Oksanka [162]

Answer:

3x⁴ + x³ + 3 x² - 18 x + 4

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Bruno uses a piece of wrapping paper with dimensions 1 and one-fourth feet by 3 feet to wrap a gift. What is the total area of t

8_murik_8 [283]

The area of the paper used to wrap the gift is 3 3/4 square feet

<h3>How to determine the total area?</h3>

The dimension is given as:

1 1/4 by 3

The area is the product of the dimensions.

So, we have

Area = 1 1/4 * 3

Express as an improper fraction

Area = 5/4 * 3

Evaluate

Area = 15/4

Rewrite as:

Area = 3 3/4

Hence, the area of the paper used to wrap the gift is 3 3/4 square feet

Read more about areas at:

brainly.com/question/24487155

#SPJ1

8 0

2 years ago

Drag each equation and coordinate to the correct location on the table. Not all equations or coordinates will be used. In the ta

Elena L [17]

Answer:

Standard Form Equivalent Form Extreme Values

y=x^2-6x+17 (x-3)^2+8 (3,8)

y=x^2+8x+21 (x+4)^2+5 (-4,5)

y=x^2-16x+60 (x-8)^2-4 (8,-4)

Step-by-step explanation:

1) Standard form:

y=x^2-6x+17

Equivalent Form:

Can be found using completing the square method.

$y=x^2-6x+17\\y=x^2-2(x)(3)+(3)^2-(3)^2+17\\y=(x-3)^2-9+17\\y=(x-3)^2+8$

So, Equivalent form is: (x-3)^2+8

Extreme value:

Extreme values are basically the minimum and maximum value of the function.

Minimum Value will be found by finding derivative of the function:

The derivate is: 2x-6

Now, put the derivate equal to zero: 2x-6 = 0

$2x=6\\x=6/3 \\x=3$

Maximum value can be found by putting minimum value in the given function:

Put x = 3 and solve:

$(3)^2-6(3)+17\\9-18+17\\9-1\\=8\\$

So, the extreme values is: (3,8)

2) Standard form:

y=x^2+8x+21

Equivalent Form:

Can be found using completing the square method.

$y=x^2+8x+21\\y=x^2+2(x)(4)+(4)^2-(4)^2+21\\y=(x+4)^2-16+21\\y=(x+4)^2+5$

So, Equivalent form is: (x+4)^2+5

Extreme value:

Extreme values are basically the minimum and maximum value of the function.

Minimum Value will be found by finding derivative of the function:

The derivate of x^2+8x+21 is: 2x+8

Now, put the derivate equal to zero:

$2x+8 = 0\\2x=-8\\x=-8/2 \\x=-4$

So, minimum value is: -4

Maximum value can be found by putting minimum value in the given function:

Put x = -4 and solve:

$x^2+8x+21\\=(-4)^2+8(-4)+21\\=16-32+21\\=5$

So, Maximum value is: 5

So, the extreme values is: (-4,5)

3) Standard form:

y=x^2-16x+60

Equivalent Form:

Can be found using completing the square method.

$y=x^2-16x+60\\y=x^2-2(x)(8)+(8)^2-(8)^2+60\\y=(x-8)^2-64+60\\y=(x-8)^2-4$

So, Equivalent form is: (x-8)^2-4

Extreme value:

Extreme values are basically the minimum and maximum value of the function.

Minimum Value will be found by finding derivative of the function:

The derivate of x^2-16x+60 is: 2x-16

Now, put the derivate equal to zero:

$2x-16 = 0\\2x=16\\x=16/2 \\x=8$

So, minimum value is: 8

Maximum value can be found by putting minimum value in the given function:

Put x = 8 and solve:

$x^2-16x+60\\=(8)^2-16(8)+60\\=64-128+60\\=-4$

So, Maximum value is: -4

So, the extreme values is: (8,-4)

4 0

3 years ago

Read 2 more answers