A washer has outer radius 
and inner radius 
![\displaystyle V = \int_0^1 \pi\Big[ \left( 2 - x^2 \right)^2 - \left( 2 - \sqrt{x}\right)^2\Big] dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20V%20%3D%20%5Cint_0%5E1%20%5Cpi%5CBig%5B%20%5Cleft%28%202%20-%20x%5E2%20%5Cright%29%5E2%20-%20%5Cleft%28%202%20-%20%5Csqrt%7Bx%7D%5Cright%29%5E2%5CBig%5D%20dx)
Somebody Please Help!!!
1 answer:
Answer:
11) 153, 85, 238 12) 12, 15, 27
Step-by-step explanation:
To find the area of these shapes, you have to cut them into two seperate shapes as shown the in the image: Shape 1 and Shape 2
11) Let Shape 1 be the rectangle: 17×9=153
let Shape 2 be the triangle: ×10×8.5=42.5×2=85
Total area: 153 + 85 = 238
12) Let cut this shape vertically where you'll have a rectangle thats 3 by 4 and a rectangle that's 5 by 3
Shape 1: 3×4=12
Shape 2: 5×3=15
Total area: 15 + 12 = 27
You might be interested in