Answer:
(a) 9.9321*10^{-11}
(b) 6.0498*10^{-11}
(c) 7.7120^{-11}
(d) 1.6417 times more probable
Step-by-step explanation:
(a) The probability of winning a 6/49 lottery is given by:
(b) The probability of winning a 6/53 lottery is given by:
(c) The probability of winning a 6/51 lottery is given by:
(d) The ratio between the probabilities of winning the 6/49 lottery and winning the 6/53 lottery is:
It is 1.6417 times more probable.
Comment.
9A
Let's use (a) as an example. What number is in front of the x inside be brackets? If I gave you the choice of 1,2,3,4,5 which number is it out of those 5?
If you chose 5, you have the second best answer. You are reading outside the brackets. Not what we need.
If you choose 1, you are well on your way. There is a 1 beside the x.
Now go to the outside of the brackets. What's in front of the x? 1,2,3,4,5.. There is only one number you can choose. It's a 5. So the result outside the brackets is 5x. How did 1x become 5x? You had to put a 5 on the blank to the left of the brackets..
5(5 + x) = 5x + ___ What goes on the line to the right of 5x? Rule whatever you do to one side of a plus sign inside the brackets, you must do to the other side of the plus sign.
It becomes 5*5
So the blank is filled with 25. And here's the answer.
5(5 + x) = 5x + 25 <<<< answer..
Stop don't do anything more. 5x and 25 are not like terms. They don't mix
9B
Let's make this one brief so that you have something to do. What did you multiply 5 by to get 10? You should answer 2.
2(x + 5) = ___ x + 10
What you do on one side of the plus sign, you must do on the other. So what's in front of the x on the right?
2(x + 5) = 2x + 10 <<<< answer
Answer: SHE GOT 13 MONTHS YES SHE DO, 13 MONTHS LEFT IS ANSWER
Step-by-step explanation:
13.
1st: split the 1 shape into 2 shapes. (spit across to where you see one right angle(top), and a trapezoid(bottom)
2nd: now what i did was fill that gap to where the total height is 9 and the total length is 7. ( if you don't want to do that it is fine )
3rd: for the top do 5 times 2 = 10
4th: for the bottom do 4 times 5 = 20
5th: add 10 (top) and 20 (bottom) = 30
P(t) = P₀ e^(kt)
<span>Where P₀ is the initial population, </span>
<span>P(t) is the population after "t" time. </span>
<span>t is your rate (can be hours, days, years, etc. in this case, hours) </span>
<span>k is the growth constant for this particular problem. </span>
<span>So using the information given, solve for k: </span>
<span>P₀ = 2000 </span>
<span>P(4) = 2600 </span>
<span>P(t) = P₀ e^(kt) </span>
<span>2600 = 2000e^(k * 4) </span>
<span>1.3 = e^(4k) </span>
<span>Natural log of both sides: </span>
<span>ln(1.3) = 4k </span>
<span>k = ln(1.3) / 4 </span>
<span>Now that we have a value for "k", use that, the same P₀, then solve for P(17): </span>
<span>P(t) = P₀ e^(kt) </span>
<span>P(17) = 2000 e^(17ln(1.3) / 4) </span>
<span>Using a calculator to get ln(1.3) then to simplify from there, we get: </span>
<span>P(17) ≈ 2000 e^(17 * 0.262364 / 4) </span>
<span>P(17) ≈ 2000 e^(4.460188 / 4) </span>
<span>P(17) ≈ 2000 e^(1.115047) </span>
<span>P(17) ≈ 2000 * 3.0497 </span>
<span>P(17) ≈ 6099.4 </span>
<span>Rounded to the nearest unit: </span>
<span>P(17) ≈ 6099 bacteria hope i could help =)))</span>
