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ludmilkaskok [199]
2 years ago
14

Write the equation of a line perpendicular to y=-12x+2 going through (0,-1)

Mathematics
1 answer:
DanielleElmas [232]2 years ago
5 0

             \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

          <em>Write the equation of a line perpendicular to y=-12x+2 going </em>

<em>            through (0, -1)</em>

<em />

<em>      </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

        First, let's take a look at our provided information:-

  • A line \text{y=-12x+2}
  • A point (0, -1)
  • The line \text{y=-12x+2} is perpendicular to the line that goes through (0, -1)

     If two lines are perpendicular to each other, their slopes are opposite reciprocals of each other.

   So we take the slope of the given line, which is -12, change its sign from minus to plus:-

\Large\textit{12}

And now, We flip the number over:-

\Large\text{$\displaystyle\frac{1}{12}$}

Now that we've found the slope of the line, let's find its equation.

     The first step is to write it in point-slope form as follows:-

\longmapsto\sf{y-y_1=m(x-x_1)}

Replace letters with numbers,

\longmapsto\sf{y-(-1)=\displaystyle\frac{1}{12}(x-0)}

On simplification,

\longmapsto\sf{y+1=\displaystyle\frac{1}{12} (x-0)}

On further simplification,

\longmapsto\sf{y+1=\displaystyle\frac{1}{12} x}

Subtracting 1 on both sides,

\longmapsto\sf{y=\displaystyle\frac{1}{12} x-1}

\Uparrow\texttt{Our equation in slope-intercept form}

<h3>Good luck with your studies.</h3>

#TogetherWeGoFar

\rule{300}{1}

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