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Vladimir79 [104]
2 years ago
8

4) Find m.

Mathematics
1 answer:
Alja [10]2 years ago
3 0

Answer: QP=11.18cm;

m=Q42*;m<R=48*

Step-by-step explanation:

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Help me fill this out! please be honest and help me , i'll mark you brainlesst
faust18 [17]

Answer/Step-by-step explanation:

1. The vertex of am angle is formed when two lines join together. The vertex of the angle shown in the diagram is located outside the circle.(<R)

2. The lines that created <FRT (lines FR & TR) are secants

3. The major arc = FT = 140°

minor arc = QS = 44°

4. Formula of Exterior angles of a circle = (major arc - minor arc)/2

x = (140 - 44)/2

x = 96/2

x = 48°

5 0
3 years ago
How to subtract a radical from a whole number?
OLEGan [10]
Although a radical cannot be expressed as a terminating or recurring decimal or a fraction, it can be approximated. This approximation can be expressed as a decimal or a fraction. So if a decimal, ordinary rules of arithmetic apply.
If a fraction, ordinary rules for subtracting fractions apply.
EXAMPLE
99/70 is a good approximation for √2. Let’s see how we would calculate 5-√2=5-99/70=(350-99)/70=251/70=3⁴¹⁄₇₀.
√2=1.4142 to 4 places of decimals. So 5-√2=5-1.4142=3.5858. When we work out 3⁴¹⁄₇₀ as a decimal to 4 places we get 3.5857.
So treat radicals like other real numbers. When giving an answer you may need to say what accuracy you are using (so many decimal places) or the question may tell you how many decimal places are needed.
6 0
3 years ago
∆ABC and ∆PQR are congruent under the correspondence: ABC ↔ RQP
valentinak56 [21]

Answer:

Please check the explanation.

Step-by-step explanation:

Given

ABC ↔ RQP

It means

  • ΔABC ≅ ΔABC

Please check the attached diagram.

Here,

  • A ↔ R
  • B ↔ Q
  • C ↔ P

Parts of ΔABC that correspond to

(i) PQ

From the diagram, it is clear that:

PQ corresponds to CB

(ii) ∠Q

∠Q corresponds to ∠B

(iii) RP

RP corresponds to AC

8 0
2 years ago
Find the inverse of h(x)= -x^5+2 step by step
nikdorinn [45]

Hi there!

\large\boxed{y = \sqrt[5]{-(x-2)}}

h(x) = -x^{5} + 2

Rewrite h(x) as y:

y = -x^5 + 2

Switch the x and y variables:

x = -y^{5} + 2

Isolate y by subtracting 2 from both sides:

x - 2 = -y^5

Multiply both sides by -1:

-(x-2) = y^5

Take the 5th root of both sides:

y = \sqrt[5]{-(x-2)}

6 0
2 years ago
Which of the following is a fourth degree polynomial function?
kotegsom [21]

Answer:

Dude this is algebra.

Step-by-step explanation:

8 0
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