The question doesn't seem to be a complete one ..
You reject the Null Hypothesis only if the p-value is less than alpha.
p < 0.01
To find the p-value, you need to look up test value 2.07 in a standard normal table. The p-value is probability that Z > 2.07. For a two-tailed test, you include both positive and negative cases. |Z| > 2.07.
When you look up 2.07 you get about 0.98.
This means there is about 2% chance Z > 2.07 or 4% chance |Z| > 2.07.
For the two-tailed test we use p = 0.04
.04 > .01
Therefore we do Not reject the Null Hypothesis.
Answer:
(a) x=-3.15cm
(b)y=0cm
Step-by-step explanation:
Locate the point (4.2,4.9) cm and draw the vector 4.5i+3.j with the origin at this point, the end of the vector is going to be in the point (8.7,7.9). With point (2.2,0), after searching, draw a line to the right to represent that the direction of the field is toward the positive x-axis.
Draw a line in each point in the opposite direction of the field in that point, the point where these lines intersect each other is the position of the particle.
Is the point (-3.15,0)cm
(a) x=-3.15cm
(b)y=0cm
Answer:
<B=41.81
Step-by-step explanation:
Use Trigonometry Sine
Sinθ=2/3
Sinθ⁻¹*Sinθ=(2/3)*Sinθ⁻¹
Sinθ=41.81
Answer:
40%
Step-by-step explanation:
Total students = 25
Boys = 15
Girls = 25 - 15 = 10
Percent of girls = 10/25
Percent is out of 100.
=> 10/25 = x/100
=> Cross multiply
=> 25 * x = 100 * 10
=> 25x = 1000
=> 25x/25 = 1000/25
=> x = 40
So, 40% are girls