All categories

3 years ago

NEED ANSWERS ASAP PLEASE

Mathematics

1 answer:

weqwewe [10]3 years ago

3 0

Answer:

Step-by-step explanation:

u can see its a right triangle u can see its kinda like 3-4-5 right triangle

75/5 = 15

21/3 = 7

ok so it doesn't work

now

75^2 - 21^2 = 5184

square root of 5184 = 72

You might be interested in

Slove equations with variables on both sides9 + 3f = 2f

Vera_Pavlovna [14]

Given 9 + 3f = 2f

9 = 2f - 3f

9 = -f

f = -9

4 0

1 year ago

Write the numbers -2.1, -1.8, -2.5 and -2.7 from greatest to least.

Fiesta28 [93]

Answer:

-1.8, -2.1, -2.5, -2.7

Step-by-step explanation:

the bigger the negative number, the smaller it is

5 0

3 years ago

Read 2 more answers

The coordinates of the vertices of / are G(–2, 3), H(–1, 2), and I(–3, 1). If / is reflected across the x-axis to create /, find

valkas [14]

Answer:

A. (–2, –3)

that is the answer

3 0

4 years ago

(cotx+cscx)/(sinx+tanx)

Butoxors [25]

Answer: $\bold{\dfrac{cot(x)}{sin(x)}}$

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

$\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)$

$\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)$

$\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}$

6 0

3 years ago

What's the square root of 0.4 repeating

avanturin [10]

The answer depends on knowing that 0.4444.... is equal to 4/9;
<span>the square root of 4/9 is 2/3 = 0.6666....</span>

6 0

3 years ago