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3 years ago

In the function y= 1/3x^2,

Mathematics

2 answers:

Keith_Richards [23]3 years ago

5 0

I believe its your answer would be C!

Liono4ka [1.6K]3 years ago

4 0

C is the correct answer to your question

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What is the sum of -4/7 and 6/7 A) -2/7 B) 2/7 C) -10/7 D) 10/7

kari74 [83]

2/7. just add the -4 and 6 together and use the 7 as the denominator

3 0

3 years ago

The two plots below show the heights of some sixth graders and some seventh graders of a school:/Users/tylerleaird/Desktop/Scree

fenix001 [56]

0.5 will be rounded to 1.0
1.2 will be rounded to 1.0
1.7 will be rounded to 2.0
3.4 will be rounded to 3.0

7 0

3 years ago

Find the difference, –8 – (–5). Then check your work by writing the equivalent addition sentence.

pav-90 [236]

Answer:

-3

Step-by-step explanation:

double negative = positive so the equation turns into -8+5. add 5 by going 5 spaces closer to 0 on a number line. the answer is -3.

another equation is -3-5=-8

hope this helped! =)

4 0

2 years ago

Which of the following expressions represents the area, in square meters, of the regular decagon (10-sided polygon) with 3.25 me

raketka [301]

Answer:

A = P * a / 2

A = 81.25

Step-by-step explanation:

We have that there is a corresponding formula for a regular decagon, which depends on the apothem and the perimeter, it is the following:

A = P * a / 2

In this case, the perimeter is the sum of all the sides, that is, 10 sides, therefore:

P = 10 * 3.25

P = 32.5 meters

We replace:

A = 32.5 * 5/2

A = 81.25

Which means that for that regular decagon, the area is 81.25 square meters.

3 0

3 years ago

find the number of subsets of s = 1 2 3 . . . 10 that contain exactly 4 elements including 3 or 4 but not both.

Anna007 [38]

Answer:

112

Step-by-step explanation:

Let A be a subset of S that satisfies such condition.

If 3∈A, then the other three elements of A must be chosen from the set B={1,2,5,6,7,8,9,10} (because 3 cannot be chosen again and 4 can't be alongside 3). B has eight elements, then there are $\binom{8}{3}=56$ ways to select the remaining elements of A (the binomial coefficient counts this). The remaining elements determine A uniquely, then there are 56 subsets A.

If 4∉A, we have to choose the remaining elements of A from the set B={1,2,5,6,7,8,9,10}. B has eight elements, then there are $\binom{8}{3}=56$ ways to select the remaining elements of A. Thus, there are 56 choices for A.

By the sum rule, the total number of subsets is 56+56=112

4 0

4 years ago