✿————✦————✿————✦————✿
The answer is: <u>2(k2−4k)(2c+5)</u>
✿————✦————✿————✦————✿
Step:
* Consider 2ck2+5k2−8ck−20k. Do the grouping 2ck2+5k2−8ck−20k=(2ck2+5k2) +(−8ck−20k), and factor out k2 in the first and −4k in the second group.
* Factor out the common term 2c+5 by using the distributive property.
* Rewrite the complete factored expression.
✿————✦————✿————✦————✿
Answer:
JL = 78
Step-by-step explanation:
MN is a midsegment. Based on the midsegment theorem,
MN = ½(JL)
MN = 5x - 16
JL = 4x + 34
Plug in the value
5x - 16 = ½(4x + 34)
5x - 16 = ½*4x + ½*34
5x - 16 = 2x + 17
Collect like terms
5x - 2x = 16 + 17
3x = 33
Divide both sides by 3
x = 11
✔️JL = 4x + 34
Plug in the value of x
JL = 4(11) + 34
JL = 44 + 34
JL = 78
Answer:
g (f (-3)) = -9
Step-by-step explanation:
Given:
Graphs of f(x) and g(x) are given
From the given graphs:
Finding g ( f (-3) ):
-----> g ( f (-3) )
-----> g(5)
-----> -9
so,
g ( f (-3) ) = -9
Here i how I would do it:<span>f(x)=−<span>x2</span>+8x+15</span>
set f(x) = 0 to find the points at which the graph crosses the x-axis. So<span>−<span>x2</span>+8x+15=0</span>
multiply through by -1<span><span>x2</span>−8x−15=0</span>
<span>(x−4<span>)2</span>−31=0</span>
<span>x=4±<span>31<span>−−</span>√</span></span>
So these are the points at which the graph crosses the x-axis. To find the point where it crosses the y-axis, set x=0 in your original equation to get 15. Now because of the negative on the x^2, your graph will be an upside down parabola, going through<span>(0,15),(4−<span>31<span>−−</span>√</span>,0)and(4+<span>31<span>−−</span>√</span>,0)</span>
To find the coordinates of the maximum (it is maximum) of the graph, you take a look at the completed square method above. Since we multiplied through by -1, we need to multiply through by it again to get:<span>f(x)=31−(x−4<span>)2</span></span><span>
Now this is maximal when x=4, because x=4 causes -(x-4)^2 to vanish. So the coordinates of the maximum are (4,y). To find the y, simply substitute x=4 into the equation f(x) to give y = 31. So it agrees with the mighty Satellite: (4,31) is the vertex.</span>
