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kvasek [131]
3 years ago
10

What is the quadratic formula?

Mathematics
2 answers:
sergey [27]3 years ago
8 0

Answer:

Step-by-step explanation:

tatiyna3 years ago
3 0

Answer:

x = \frac{-b±\sqrt{b^2-4ac} }{2a}

Ignore the capital A for this equation when it is ax^2+bx+c=0

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I need help on this problem
Helen [10]

Answer:

if you solve it for the t your answer would be: pt+30pte−0.2t=600

but if you solved it for the p your answer would be: p=600t(1+30e−0.2t)

hope it works, sweete

8 0
3 years ago
Given a single die (six possible values 1, 2, 3, 4, 5 or 6), what is the probability of throwing a number less than or equal to
Sedbober [7]

Answer:

66.6 or 67%

Step-by-step explanation:

100/6= 16.66666667

16.66666667 × 4 = 67%

6 0
3 years ago
How to solve 3(5-e)+2=10
miss Akunina [59]
<span>Simplifying 3(5 + -1e) + 2 = 10 (5 * 3 + -1e * 3) + 2 = 10 (15 + -3e) + 2 = 10 Reorder the terms: 15 + 2 + -3e = 10 Combine like terms: 15 + 2 = 17 17 + -3e = 10 Solving 17 + -3e = 10 Solving for variable 'e'. Move all terms containing e to the left, all other terms to the right. Add '-17' to each side of the equation. 17 + -17 + -3e = 10 + -17 Combine like terms: 17 + -17 = 0 0 + -3e = 10 + -17 -3e = 10 + -17 Combine like terms: 10 + -17 = -7 -3e = -7 Divide each side by '-3'. e = 2.333333333 Simplifying e = 2.333333333</span>
6 0
3 years ago
Read 2 more answers
What the value of the expression 4x^3 when x = -2
bekas [8.4K]

Answer:

-32

Step-by-step explanation:

All you have to do is put the -2 in place of x

4x^3

4(-2)^3

4(-2 x -2 x -2)

4( 4 x -2)

4(-8)

-32

3 0
4 years ago
Apply the appropriate mathematical operation to solve this fulcrum problem.
ale4655 [162]
<h2>Hello!</h2>

The answer is:

The second distance (distance_{2}) is equal to 7.5 feet.

<h2>Why?</h2>

Since we are given two forces acting at distance, torque will be created. We are given two forces and one distance, so, to calculate the other distance required to balance the system (solve this fulcrum problem), we need to write the following equation:

Torque_{1}=Torque_{2}

Where,

Torque=F*Distance

We are given,

Force_{1}=Weight_{1}=150lb\\Force_{2}=Weight_{2}=30lb\\distance_{1}=15ft\\

So, substituting and calculating, we have:

Torque_{1}=Torque_{2}

Weight_{1}*distance_{1}=Weight_{2}*distance_{2}

150lb*15ft=300lb*distance_{2}

distance_{2}=\frac{150lb*15ft}{300lb}=7.5ft

Hence, the second distance (distance_{2}) is equal to 7.5 feet.

It's a logical solution since the second force is twice the first force and it means that the second distance must be equal to half the first distance in order to maintain the equilibrium condition.

Have a nice day!

8 0
3 years ago
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