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Brums [2.3K]
3 years ago
11

If a graduated cylinder reads 32.6 ml of water and the level rises when a 6.8 ml object is placed in it, what is the

Physics
1 answer:
Andre45 [30]3 years ago
7 0

Answer:

39.4 ml

Explanation:

The displacement is the original volume plus the volume of the other object.

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A particle with a charge of 6.40 nC is in a uniform electric field directed to the left. Another force, in addition to the elect
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Explanation:

It is given that,

Charge in the particle, q=6.4\ nC=6.4\times 10^{-9}\ C

Work done by the force, W_1=6.5\times 10^{-5}\ J

The kinetic energy of the particle, E_k=3.7\times 10^{-15}\ J

(a) Using the conservation of energy to find the work done by the electric force. Let it is given by W_2 as :

W_1+W_2=E_k

W_2=E_k-W_1

W_2=3.7\times 10^{-15}-6.5\times 10^{-5}

W_2=-6.49\times 10^{-5}\ J

(b) Let V is the electric potential. the work done by the electric charge per unit positive charge is called its electric potential. Mathematically,

\Delta V=\dfrac{W_2}{q}

\Delta V=\dfrac{-6.49\times 10^{-5}}{6.4\times 10^{-9}}

\Delta V=10.14\times 10^3\ volts

\Delta V=10.14\ kV

Hence, this is the required solution.

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4 years ago
The diagram is an illustration of<br> NO LINKS
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Answer:

A longitudinal wave

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3 years ago
The same force is applied to two skateboards. One rolls across the room and the other moves a few feet and comes to a stop. Wher
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3 years ago
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A plane has a takeoff speed of 88.3 m/s and requires 1365 m to reach that speed. Determine the acceleration
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3 years ago
A 20.0 Ω, 15.0 Ω, and 7.00 Ω resistor are connected in parallel to an emf source. A current of 7.00 A is in the 15.0 Ω resistor.
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PART A)

Equivalent resistance in parallel is given as

\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}

now we have

\frac{1}{R} = \frac{1}{20} + \frac{1}{15} + \frac{1}{7}

R = 3.85 ohm

PART B)

since potential difference across all resistance will remain same as all are in parallel

so here we can use ohm's law

V = iR

As we know i = 7 A current flows through 15 ohm resistance

V = (7 A)(15 ohm) = 105 volts

PART C)

Similarly ohm's law for 20 ohm resistance we can say

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