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AleksandrR [38]
4 years ago
7

A 20.0 Ω, 15.0 Ω, and 7.00 Ω resistor are connected in parallel to an emf source. A current of 7.00 A is in the 15.0 Ω resistor.

Calculate the equivalent resistance of the circuit. Answer in units of Ω.
What is the potential difference across the source?
Answer in units of V.
Calculate the current in the 20.0 Ω resistor. Answer in units of A.
Physics
2 answers:
Arlecino [84]4 years ago
7 0
<h2>Answer:</h2>

<u>Equivalent Resistance = 3.85 ohm</u>

<u>Voltage is 105 volts</u>

<u>Current is 5.25 A</u>

<h2>Explanation:</h2>

<h3>Part 1</h3>

Equivalent resistance in parallel is given as

1/Re = 1/R1 + 1/R2  + 1/R3

By putting the values

1/Re = 1/20 + 1/15 + 1/7

Equivalent Resistance = 3.85 ohm

<h3> Part 2 By Using Ohm Law</h3>

V = IR

Since i = 7  so

Voltage = (7 A)(15) =

V = 105 volts

<h3>Part 3</h3>

According to Ohms law

V = IR

105 = I (20)

I = 5.25 A

Lady bird [3.3K]4 years ago
3 0

PART A)

Equivalent resistance in parallel is given as

\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}

now we have

\frac{1}{R} = \frac{1}{20} + \frac{1}{15} + \frac{1}{7}

R = 3.85 ohm

PART B)

since potential difference across all resistance will remain same as all are in parallel

so here we can use ohm's law

V = iR

As we know i = 7 A current flows through 15 ohm resistance

V = (7 A)(15 ohm) = 105 volts

PART C)

Similarly ohm's law for 20 ohm resistance we can say

V = iR

105 = i(20 ohm)

i = 5.25 A

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