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2 years ago

5

What is the gravity of sombrero galaxy compared to earth?

2 answers:

Aleksandr [31]2 years ago

7 0

the Sombrero galaxy, is one of the largest mosaics ever assembled from Hubble observations. The hallmark of the nearly edge-on galaxy is a brilliant, white, bulbous core encircled by thick dust lanes comprising the spiral structure of the galaxy. This dust lane is the site of star formation in the galaxy. The center of M104 is thought to be home to a massive black hole. I hope this helped

postnew [5]2 years ago

4 0

The Sombrero galaxy, is one of the largest mosaics ever assembled from Hubble observations. The hallmark of the nearly edge-on galaxy is a brilliant, white, bulbous core encircled by thick dust lanes comprising the spiral structure of the galaxy. This dust lane is the site of star formation in the galaxy. The center of M104 is thought to be home to a massive black hole.

Hubble easily resolves the Sombrero galaxy’s rich system of globular clusters, estimated to be nearly 2,000 in number — 10 times more than the number of globular clusters in our Milky Way galaxy.

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A physics student stands on a cliff overlooking a lake and decides to throw a softball to her friends in the water below. She th

aliina [53]

Answer:

58.5 m

Explanation:

First of all, we need to find the total time the ball takes to reach the water. This can be done by looking at the vertical motion only.

The initial vertical velocity of the ball is

$u_y = u sin \theta$

where

u = 21.5 m/s is the initial speed

$\theta=33.5^{\circ}$ is the angle

Substituting,

$u_y = (21.5) sin 33.5^{\circ} =11.9 m/s$

The vertical position of the ball at time t is given by

$y = h + u_y t + \frac{1}{2}gt^2$

where

h = 13.5 m is the initial heigth

$g = -9.8 m/s^2$ is the acceleration of gravity (negative sign because it points downward)

The ball reaches the water when y = 0, so

$0 = h + u_yt +\frac{1}{2}gt^2\\0 = 13.5 +11.9 t - 4.9t^2$

Which gives two solutions: t = 3.27 s and t = -0.84 s. We discard the negative solution since it is meaningless.

The horizontal velocity of the ball is

$u_y = u cos \theta = (21.5) cos 33.5^{\circ} =17.9 m/s$

And since the motion along the horizontal direction is a uniform motion, we can find the horizontal distance travelled by the ball as follows:

$d= u_x t = (17.9)(3.27)=58.5 m$

3 0

2 years ago

Pls help will give brainlest

Karo-lina-s [1.5K]

Respon

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7 0

2 years ago

Read 2 more answers

Can you please help - the answer I got so far is 7.624 but when I enter it in my homework in Quest, it i stating that this answe

torisob [31]

Answer:

-7.04

Explanation:

9.8 multipled by -0.719 b

6 0

2 years ago

An ambulance is traveling north at 55.9 m/s, approaching a car that is also traveling north at 28.4 m/s. The ambulance driver he

wlad13 [49]

Answer:

915 Hz

Explanation:

The observed frequency from a sound source is given as

f₀ = f [(v + v₀)/(v+vₛ)]

where

f₀ = observed frequency of the sound by the observer = ?

f = actual frequency of the sound wave = 983 Hz

v = actual velocity of the sound waves = 343 m/s

vₛ = velocity of the source of the sound waves = 55.9 m/s

v₀ = velocity of the observer = 28.4 m/s

f₀ = 983 [(343+28.4)/(343+55.9)]

f₀ = 915.2 Hz = 915 Hz

6 0

3 years ago

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user100 [1]

Answer:

D is not the a vector quantities

4 0

3 years ago