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svetlana [45]
3 years ago
11

Which expression is equivalent to 6x^2+16x-6

Mathematics
1 answer:
AveGali [126]3 years ago
6 0

The answer is (2x+6)(3x-1)

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I WILL NAME YOU BRAINLIEST AND GIVE YOU ALL MY POINTS IF YOU SOLVE THIS!!!!! In the diagram, each shape has a value and the sums
cluponka [151]

Answer:

...

Step-by-step explanation:

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3 years ago
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Sylvia has just discovered that the valve on her cement truck failed during the night and that all the contents ran out to form
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The volume would be exactly 256.76
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3 years ago
Solve by completing the square. <br> x2-6x+8 <br> Show solving steps please.
devlian [24]

Answer:

(x−2)(x−4)

Step-by-step explanation:

Let's factor x2−6x+8

x2−6x+8

The middle number is -6 and the last number is 8.

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(x+_)(x+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get -6

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Can you think of the two numbers?

Try -2 and -4:

-2+-4 = -6

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(x-2)(x-4)

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4 0
3 years ago
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quizlet "it is closed under addition and multiplication but not closed under subtraction or division."
deff fn [24]

Rational numbers are closed under addition ,multiplication but not closed under division

Rational number

Closure property

assume two rational numbers say x and y. the results  of addition and multiplication operations give a rational number we can say that rational number are closed under addition and multiplication . For example

rational number are not closed under division as  1 and 0 are rational number  but 1/0 is not defined but it is closed under addition  and multiplication

that is 1+0 = 1 closed under addition

          1*0 =0 closed under multiplication

but 1/0  is not defined so it is not closed under division

Hence Rational numbers are closed under addition ,multiplication but not closed under division

learn more of closure property here

brainly.com/question/28220649

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4 0
1 year ago
D= kA [T2 - T1 / L] Solve for T1
mel-nik [20]
d=\dfrac{k_A(T_2-T_1)}{T}\ \ \ \ |multiply\ both\ sides\ by\ T\\\\k_A(T_2-T_1)=dT\ \ \ \ |divide\ both\ sides\ by\ k_A\\\\T_2-T_1=\dfrac{dT}{k_A}\ \ \ \ |subtract\ T_2\ from\ both\ sides\\\\-T_1=\dfrac{dT}{k_A}-T_2\ \ \ \ \ |change\ signs\\\\\boxed{T_1=T_2-\frac{dT}{k_A}}
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