9514 1404 393
Answer:
$2,070,000
Step-by-step explanation:
The series of salaries has a first term of $40,000 and a common difference of $2,000. The sum of them is given by the formula ...
Sn = (2a1 +d(n -1))(n/2)
where a1 is the first term of the series, d is the common difference, and n is the number of terms.
In this problem, we have ...
a1 = 40,000; d = 2,000; n = 30
so the sum is ...
S30 = (2(40,000) +2,000(30 -1))(30/2) = (80,000 +58,000)(15)
S30 = 2,070,000
The teacher will earn $2,070,000 over 30 years on this salary schedule.
