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Anna11 [10]
3 years ago
8

Ordena de mayor a menor en los Ejercicios 9 a 12.

Mathematics
1 answer:
Dominik [7]3 years ago
3 0

Answer:

We are required to order the numbers from greatest to least.

So, according to the options:

1. 9.129, 9.37, 9.3, 9.219

Since, the number of digits after the decimal place are not same, so we make them equal by adding 0 at the end. SO, we have,

9.129, 9.370, 9.300, 9.219

As, the ones place in each of the number is same, we look at the digit after the decimal.

Now, 9.370 and 9.300 have the same number after the decimal, so we look at the next number i.e 7 and 0 respectively.

As 7 > 0, so we get 9.370 > 9.300.

Hence, the order becomes 9.370, 9.300, 9.219, 9.129.

2. 0.012, 0.100, 0.001, 0.101

Again, as the ones place in each of the number is same, we look at the digit after the decimal.

Now, 0.101 and 0.100 have the same number till two places after the decimal, so we look at the next number i.e. 1 and 0 respectively.

As 1 > 0, so we have 0.101 > 0.100

Hence, the order becomes 0.101, 0.100, 0.012, 0.001.

3. 5.132, 5.123, 5.312, 5.231

Again, as the ones place in each of the number is same, we look at the digit after the decimal.

Now, 5.132 and 5.123 have the same number after the decimal, so we look at the next number i.e. 3 and 2 respectively.

As 3 > 2, so we get 5.132 > 5.123.

Hence, the order is 5.312, 5.231, 5.132, 5.123.

4. 62.905, 62.833, 62.950, 62.383

As the ones place in each of the number is same, we look at the digit after the decimal.

Now, 62.905 and 62.950 have the same number after the decimal, so we look at the next number i.e. 0 and 5 respectively.

As 5 > 0, so we get 62.950 > 62.905.

Hence, the order becomes 62.950, 62.905, 62.833, 62.383.

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QUESTION 1

The given equation is :

2(y - 3) = 4
We want to solve for y. This means we have to isolate y on one side of the equation while all other constants are also on the other side of the equation,

We first divide both sides by 2 to obtain,

\frac{2(y - 3)}{2} = \frac{4}{2}

We cancel out the common factors to get,

y - 3 = 2

We now group like terms to get,

y = 3 + 2

We simplify to obtain,

y = 5

QUESTION 2

The given equation is

2x + 5y = 10
We want to solve for x. This means that we need to isolate x on one side of the equation, while all other variables and constant are also on the other side of the equation.

This implies that,

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We now divide through by 2, to obtain,

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This will now give us,

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We want to solve for y. This means that we need to isolate y on one side of the equation, while all other variables and constants are also on the other side of the equation.

We first of all group all the y terms on one side of the equation to obtain,

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The given equation is,

3(2x + 4) = 2 + 6x + 10

We want to solve for x. This means that we need to isolate x on one side of the equation, while all other variables and constant are also on the other side of the equation.

Let us first expand the brackets to get,

6x + 12 = 2 + 6x + 10
This implies that

6x + 12 = 6x + 12

We group like terms to get,

6x - 6x = 12 - 12

We now simplify both sides to get,

0x = 0

We don't want x to vanish, so let us try to divide both sides by zero to get,

x = \frac{0}{0}

This is an indeterminate form, which implies that, x has infinitely many solutions. This means that all the real numbers are solution to the equation.

\therefore \: x \in \: R

QUESTION 5

The given equation is,

y = - 3x + 6

We want to solve for x, so we add the additive inverse of 6, which is -6 to both sides of the equation to get,

y - 6 = - 3x

We rewrite this to obtain,

- 3x = y - 6

We divide through by -3 to get,

\frac{ - 3x}{ - 3} = \frac{y}{ - 3} - \frac{6}{ - 3}

This will give us,

x = - \frac{y}{3} + 2

or

x= 2 - \frac{1}{3} y
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