We know that
The sum of the lengths of any two sides of a triangle is greater than the length of the third side (Triangle Inequality Theorem)
Let
A------> Lincoln, NE
B------> Boulder, CO
C------> third city
we know that
in the triangle ABC
AB=500 miles
BC=200 miles
AC=x
Applying the Triangle Inequality Theorem
1) 500+200 > x------> 700 > x------> x < 700 miles
2) 200+x > 500----> x > 500-200------> x > 300 miles
the solution for x is
300 < x < 700
the interval is------> (300,700)
the possible distances, d, in miles, between Lincoln, NE, and the third city, are in the range between 300 and 700 miles
Answer:
How would you represent the expression "any position"?
Step-by-step explanation:
Answer:
(f+g)(x) = x^2 +10x +7
Step-by-step explanation:
(f+g)(x) = f(x) +g(x) = (15x +7) +(x^2 -5x)
= x^2 +x(15 -5) +7
= x^2 +10x +7
They are both equal. 96/12=8
And 8x12=96.
Hope that helped!
Answer:
A: 5
B: 6
C: 3x^2 - 2x
D: 8
E: 22
Step-by-step explanation:
A: (-1)^2 + 4 = 5
B: (-4)^2 +4 = 16
2 x (-3) -4 = -10,
16-10=6
C: 3(x^2 + 4) = 3x^2 + 12
3x^2 + 12 -2x -4, simplify
3x^2 - 2x
D: g(3) = 2*3 -4 = 2
f(2) = 2^2 +4 = 8
E: f(3) = 3^2 + 4 = 13
g(13) = 2*13 - 4 = 22
