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Gre4nikov [31]
3 years ago
6

Will mark brainliest

Physics
1 answer:
sweet-ann [11.9K]3 years ago
3 0

Answer: Wouldn't it just be her blocks all walked in an hour added together?

Explanation: 5+2+3+2=12 so 12 blocks an hour?

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A 2.0 kg block is given an initial speed of 8.0 m/s up an incline plane of angle 30° where the coefficient of friction is 0.35.
Korvikt [17]

Answer:

4.1 m

Explanation:

Given :

Mass of the block = m = 2 kg.

Initial velocity = v_{i} = 8 m/s

Angle of the incline = α = 30°

Coefficient of friction = μ = 0.35

Distance moved up the incline is calculated using the work energy theorem.

Work done by the net force =  change in kinetic energy of the object.

Net work = work done by friction + work done by the gravity component.

(- mg sin 30 - μ mg cos 30 ) d = 1/2m v_{f}^{2} - 1/2 m v_{i}^{2}

m cancels out when divided on both sides with m.

- [(9.8 sin 30 - ( 0.35  × 9.8 × cos 30) ] d = 1/2 ( 0² - 8² )

⇒ -7.87 d = -32

⇒ Distance traveled up the incline = d = 4.0658 m = 4.1 m

8 0
4 years ago
A chemical property is a change in _____. A density B composition of matter C hardness D physical state
NemiM [27]
Composition of matter
5 0
3 years ago
Read 2 more answers
-Para lograr que una pieza de 0,300 kg de cierto metal aumente su temperatura desde 40°C a 60 °C ha sido necesario suministrarle
marishachu [46]

Answer:

parte a) el calor específico es c = 0.383 J /(gr*K)

parte b) la temperatura inicial es T inicial= 52.72 °C

Explanation:

para el primer punto la formula para el calor Q es:

Q = m * c * ( T final - T inicial )

donde

m= masa de la pieza = 0.300 kg = 300 gr

Q = flujo de energía en forma de calor= 2299 J

c = calor específico

T final = temperatura final =40°C

T inicial = temperatura inicial = 60 °C

entonces

Q = m * c * ( T final - T inicial )

c = Q / [ m* ( T final - T inicial ) = 2299 J/[ 300 gr  * ( 60 °C - 40°C )]

= 0.383 J /(gr*K)

c = 0.383 J /(gr*K)

para el segundo punto usamos la misma formula

Q = m * c * ( T final - T inicial )

pero

m= 200 gr= 0.200 kg

c=459.8 J/(kg*K) , Q =20.900 J , T final = 280 °C

Q = m * c * ( T final - T inicial )

T inicial = T final - Q/(m*c)  =280 °C - 20.900 J/(459.8 J/(kg*K)* 0.200 kg) = 52.72 °C

7 0
4 years ago
A runner makes one lap around a 200 m track in a time of 25.0 s. What was the runner's average speed?
creativ13 [48]
The answer is 8 meters per second 8m/s because 200 divided by 25 is 8 
3 0
4 years ago
Read 2 more answers
Which of the following best describes gravitational potential energy,
s2008m [1.1K]
The energy stored in an object when you lift it,
8 0
3 years ago
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