Answer:
4.1 m
Explanation:
Given :
Mass of the block = m = 2 kg.
Initial velocity = = 8 m/s
Angle of the incline = α = 30°
Coefficient of friction = μ = 0.35
Distance moved up the incline is calculated using the work energy theorem.
Work done by the net force = change in kinetic energy of the object.
Net work = work done by friction + work done by the gravity component.
(- mg sin 30 - μ mg cos 30 ) d =
m cancels out when divided on both sides with m.
- [(9.8 sin 30 - ( 0.35 × 9.8 × cos 30) ] d = 1/2 ( 0² - 8² )
⇒ -7.87 d = -32
⇒ Distance traveled up the incline = d = 4.0658 m = 4.1 m
Answer:
Given:
Temperature, T = 3.13 K
molar mass of molecular hydrogen, m = 2.02 g/mol =
Solution:
To calculate the root mean squarer or rms speed of hydrogen molecule, we use the given formula:
where
R = rydberg's constant = 8.314 J/mol-K
Putting the values in the above formula:
Answer:
The horizontal distance is 4.823 m
Solution:
As per the question:
Mass of man, m = 65.0 kg
Height of the hill, H = 5.00 m
Mass of the backpack, m' = 20.0 kg
Height of ledge, h = 2 m
Now,
To calculate the horizontal distance from the edge of the ledge:
Making use of the principle of conservation of energy both at the top and bottom of the hill (frictionless), the total mechanical energy will remain conserved.
Now,
where
KE = Kinetic energy
PE = Potential energy
Initially, the man starts, form rest thus the velocity at start will be zero and hence the initial Kinetic energy will also be zero.
Also, the initial potential energy will be converted into the kinetic energy thus the final potential energy will be zero.
Therefore,
where
v = velocity at the hill's bottom
Now,
Making use of the principle of conservation of momentum in order to calculate the velocity after the inclusion, v' of the backpack:
Now, time taken for the fall:
Now, the horizontal distance is given by:
x = v't =