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GREYUIT [131]
3 years ago
8

What is the solution to the equation x + 7 = 63? 9 16 56 70

Mathematics
1 answer:
mars1129 [50]3 years ago
4 0
The answer to your problem is 56.
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What two integers have a sum of -7 and a product of -18?
Elis [28]

Answer:

-9 and 2

Step-by-step explanation:

-9 x 2

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3 years ago
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Write the standard form of the line that contains a slope of 1/2 and y-intercept of 3. Include your work in your final answer. T
nata0808 [166]

Answer:

2y-x=6

Step-by-step explanation:

Standard form is ax+by=c.

Slope form : y=mx+n where m is slope n-y intercept.

First we write in slope form

y=\frac{1}{2}x+3

Now we can multiply both sides by 2.

2y=x+6

Subtract for each side x

2y-x=6

4 0
3 years ago
What is , 12-1x0+4÷2???
kolbaska11 [484]
2 is the answer because if you subtract 12 to 1 it will be 11 and time by 0 and it will be 0 add by 4 and divide it by 2 and it will be 2.

8 0
3 years ago
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Problem in the picture
STatiana [176]

Answer:

B)

Step-by-step explanation:

65 x 2.5 = 162.5

70 x 1.5 = 105

162.5+105=267.5

7 0
3 years ago
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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the functions given below. SEE F
Wewaii [24]

Answer:

1. P(x) ÷ Q(x)---> \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x)---> \frac{2(6x - 1)}{(3x - 1)(-3x + 2)}

3.  P(x) - Q(x)---> \frac{-2(12x - 5)}{(3x - 1)(-3x + 2)}

4. P(x)*Q(x) --> \frac{12}{(3x - 1)(-3x + 2)}

Step-by-step explanation:

Given that:

1. P(x) = \frac{2}{3x - 1}

Q(x) = \frac{6}{-3x + 2}

Thus,

P(x) ÷ Q(x) = \frac{2}{3x - 1} ÷ \frac{6}{-3x + 2}

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

\frac{2}{3x - 1}*\frac{-3x + 2}{6}

\frac{2(-3x + 2)}{6(3x - 1)}

= \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x) = \frac{2}{3x - 1} + \frac{6}{-3x + 2}

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}

\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}

\frac{12x - 2}{(3x - 1)(-3x + 2)}

= \frac{2(6x - 1}{(3x - 1)(-3x + 2)}

3. P(x) - Q(x) = \frac{2}{3x - 1} - \frac{6}{-3x + 2}

\frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 - 18x + 6}{(3x - 1)(-3x + 2)}

\frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)}

\frac{-24x + 10}{(3x - 1)(-3x + 2)}

= \frac{-2(12x - 5}{(3x - 1)(-3x + 2)}

4. P(x)*Q(x) = \frac{2}{3x - 1}* \frac{6}{-3x + 2}

P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}

P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)}

4 0
3 years ago
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