All categories

2 years ago

Elliott has 4 columns of marbles. He has 3 marbles in each column. How many marbles does he have in all? *

Mathematics

1 answer:

pochemuha2 years ago

3 0

Answer:

3*4=12

Step-by-step explanation:

the answer is 12

You might be interested in

Question 5 (1 point)

riadik2000 [5.3K]

Answer:

The area of sector AOB is 75.36 unit²

Step-by-step explanation:

Consider the provided information.

Circle O with minor arc AB=60 degrees and OA =12.

We need to find the area of sector.

Area of the sector: $A=\frac{\theta }{360} \times \pi r^2$

Substitute $\theta=60$ and r =12 in above formula.

$A=\frac{60}{360} \times 3.14\times (12)^2$

$=\frac{1}{6} \times 3.14\times 144$

$=24\times 3.14$

$=75.36$

Hence, the area of sector AOB is 75.36 unit²

8 0

3 years ago

Hellpppppppppppppppppp

Nikolay [14]

Answer:

9 + (-6)

Step-by-step explanation:

9-6=3

9 + (-6)= 3

Hope it will help you

3 0

2 years ago

Read 2 more answers

Which of the following are true

Eva8 [605]

I cannot see the question

6 0

3 years ago

Find the domain and range of the function graphed below.

anyanavicka [17]

domain = [-3 , 1)

range = [-5 , 4]

have a nice day

and this shape ( and that [ matters so be careful.

7 0

2 years ago

The differential equation in Example 3 of Section 2.1 is a well-known population model. Suppose the DE is changed to dP dt = P(a

LuckyWell [14K]

Answer:

Decreases

Step-by-step explanation:

We need to determine the integral of the DE;

$dP/dt=P(aP-b)$

$dP=P(aP-b)dt$

$1/(dP^2-bP)dP=dt$

We can solve this by integration by parts on the left side. We expand the fraction 1/P²:

$1/(d-b/P)\cdot{P^2} dP$

let

$u=d-b/P$

$du/dP=b/P^2$

$dP=$ $\int\limits {P^2/b} \, du$

$P=lnu/b$

Substitute u in:

$P=ln(d-b/P)/b$

Therefore the equation is:

$ln(d-b/P)/b=t$

We simplify:

$d-b/P=e^b^t$

$P=b/(d-e^b^t)$

As t increases to infinity P will decrease

6 0

3 years ago