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valkas [14]
3 years ago
12

What is the equation of the additive relationship represented by this table?

Mathematics
1 answer:
QveST [7]3 years ago
3 0

Answer:

-1

Step-by-step explanation: hope this helps

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Geometry math question no Guessing and Please show work
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The answer is dilation because when you dilate it produces an image that is the SAME SHAPE but DIFFERENT SIZE

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Write pqqqqrr in exponential form.
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p^1

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Step-by-step explanation:

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the axis of symmetry for the graph of the function is f(x) = 1/4x2 bx 10 is x = 6. what is the value of b?
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we have

f(x)=\frac{1}{4} x^{2} +bx+10

This is a vertical parabola open upward

The axis of symmetry is equal to the x-coordinate of the vertex

The vertex is the point (h,k)

the equation of the axis of symmetry is x=h

In this problem

x=6

so the x-coordinate of the vertex is h=6

<u>Convert the quadratic equation in vertex form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

f(x)-10=\frac{1}{4} x^{2} +bx

Factor the leading coefficient

f(x)-10=\frac{1}{4}(x^{2} +4bx)

Complete the square. Remember to balance the equation by adding the same constants to each side

f(x)-10+b^{2}=\frac{1}{4}(x^{2} +4bx+4b^{2})

Rewrite as perfect squares

f(x)+(b^{2}-10)=\frac{1}{4}(x+2b)^{2}

f(x)=\frac{1}{4}(x+2b)^{2}-(b^{2}-10)

remember that

h=6

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(x+2b)=(x-6)

2b=-6

b=-3

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f(x)=\frac{1}{4}(x-6)^{2}-((-3)^{2}-10)

f(x)=\frac{1}{4}(x-6)^{2}+1

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b=-3


8 0
4 years ago
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Dividing by 5 is equivalent to dividing by 10 and then multiplying by 2.
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63.5/5 = (63.5/10) * 2 = 6.35 * 2 =12.70 which rounds to 13.
7 0
4 years ago
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