Question

What is the y-intercept of the equation of the line that is perpendicular to the line y =

Answer 1

Answer:

y=-5/3x+20

Step-by-step explanation:

Let the equation of the required line be represented as $\[y=mx+c\]$

This line is perpendicular to the line $\[y=\frac{3}{5}x+10\]$

$\[=>m*\frac{3}{5}=-1\]$

$\[=>m=\frac{-5}{3}\]$

So the equation of the required line becomes $\[y=\frac{-5}{3}x+c\]$

This line passes through the point (15.-5)

$\[-5=\frac{-5}{3}*15+c\]$

$\[=>c=20\]$

So the equation of the required line is $\[y=\frac{-5}{3}x+20\]$

Among the given options, option 4 is the correct one.