Ask question

Ask question

All categories

3 years ago

14

(-2/5)7÷(-2/5)5=????

2 answers:

Harman [31]3 years ago

3 0

Answer:

$\frac{4}{25}$

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ ÷ $a^{n}$ ⇔ $a^{(m-n)}$

Given

$-2/5)^{7}$ ÷ $(-2/5)^{5}$

= $(-2/5)^{(7-5)}$

= $(-2/5)^{2}$

= - $\frac{2}{5}$ × - $\frac{2}{5}$ = $\frac{4}{25}$

Dafna1 [17]3 years ago

3 0

Answer:

Step-by-step explanation: So you have to take care of the brackets first (-2/5)7 gives -14/5. (-2/5)5 gives us -10/5. Therefore, we have -14/5 ÷ -10/5. According to the law of division, the sign changes to multiplication with a reciprocal of the divisor so we have -14/5 × -5/10. - × - = +. So we have 70/50. In lowest terms the answer is 7/5.

You might be interested in

Lapatulllka [165]

Could you show a picture so i could understand a little bit better?

6 0

3 years ago

Number name for 8.542

Len [333]

Number name is the same as word form

8.542 = eight and five hundred fourty-two thousandths.

hope this helps

8 0

3 years ago

Read 2 more answers

a country radio asks every 5th caller what is their favorite type of music, is this biased or unbiased?

Natasha_Volkova [10]

Answer:

unbiased, I think

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

This cube and cuboid have the same volume. The length, width and height of the cuboid are all different whole numbers. Suggest w

Zanzabum

Answer:

4hdunzkzmfindudjdkzmd

4 0

3 years ago

Write the equation for the quadratic function in standard form

Ede4ka [16]

Answer:

$y=x^2+6x+7$

Step-by-step explanation:

To write the quadratic in standard form, begin by writing it in vertex form

$y = a(x-h)^2+k$

Where (h,k) is the vertex of the parabola.

Here the vertex is (-3,-2). Substitute and write:

$y=a(x--3)^2+-2\\y=a(x+3)^2-2$

To find a, substitute one point (x,y) from the parabola into the equation and solve for a. Plug in (0,7) a y-intercept of the parabola.

$7=a((0)+3)^2-2\\7=a(3)^2-2\\7=9a-2\\9=9a\\1=a$

The vertex form of the equation is $y=(x+3)^2-2$ .

To write in standard form, convert vertex form through the distributive property.

$y=(x+3)^2-2\\y=(x^2+6x+9)-2\\y=x^2+6x+7$

8 0

4 years ago