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Gnesinka [82]
3 years ago
11

Can someone please help? I am having trouble with this question. Thank you so much.

Mathematics
1 answer:
Nikitich [7]3 years ago
7 0

Answer:

32  =  26

d 2 =  32

Step-by-step explanation: UMU

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F(x) = x^2 What is g(x)?
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graph becomes slimmer, so definitely be multipled 1/2

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3 years ago
What is the sum of the geometric series
lbvjy [14]
If S denotes the sum of the first n terms of a geometric series with first term a and common ratio r, then

S=a+ar+ar^2+\cdots+ar^{n-3}+ar^{n-2}+ar^{n-1}
rS=ar+ar^2+ar^3+\cdots+ar^{n-2}+ar^{n-1}+ar^n
\implies S-rS=a+(ar-ar)+(ar^2-ar^2)+\cdots+(ar^{n-1}-ar^{n-1})-ar^n
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S=\displaystyle\sum_{x=1}^nar^{x-1}=\sum_{x=0}^{n-1}ar^x=a\dfrac{1-r^n}{1-r}

In this case, you have a=2, r=\dfrac12, and n=16. So the value of the sum is

\displaystyle\sum_{x=0}^{15}2\left(\frac14\right)^x=2\dfrac{1-\left(\frac14\right)^{16}}{1-\frac14}\approx2.67

Rounded to the nearest whole number, the answer would be 3.
4 0
4 years ago
Read 2 more answers
Find the perimeter and area of this figure
Sonja [21]

Answer:

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Step-by-step explanation:

The area is that of a quarter-circle of radius 8 inches less half the area of a square with side length 8 inches. Two formulas are useful:

area of a circle = πr² . . . . .r = radius

area of a square = s² . . . . s = side length

Then your area is ...

A = (1/4)π(8 in)² - (1/2)(8 in)² = (64 in²)(π/4 -1/2)

A = (16π -32) in²

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The applicable formulas for the side lengths of your figure are ...

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segment BD = (8 in)√2

The perimeter is the sum of these lengths, so is ...

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_____

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8 0
3 years ago
Help with this please above
Sergio [31]
The answer is 
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pochemuha
One twelths 1/12 try to find a commen denominator or use a caculator 
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