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enot [183]
2 years ago
11

Write an example of a numerical expression

Mathematics
1 answer:
tester [92]2 years ago
8 0

Answer:

5+3 x 4 sorry this one is kinda easy lol -_-||

Step-by-step explanation:

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Which of the following equations is equivalent to S=pi r^2 h
lara31 [8.8K]

The equation that is equivalent to S=pi r^2 h is h = S/pir^2

<h3>Subject of formula</h3>

This is a way of representing a variable with another. Given the equation

S=pi r^2 h

We are to make 'h" the subject of the formula.

Divide both sides by pir^2

S/pir^2 =pi r^2 h/pir^2

h = S/pir^2

Hence the equation that is equivalent to S=pi r^2 h is h = S/pir^2

Learn more on subject of formula here: brainly.com/question/657646

#SPJ1

4 0
2 years ago
Find the exact values of cos 3 pi/4 radians sin 3 pi/4 radians HELP!
bixtya [17]
In degrees: 3π/4 radians = 135°
Angle of x=135° is in the 2nd Quadrant and has negative cos x values and positive sin x values.
cos 135° = cos ( 90° + 45°)= - sin 45° =- \frac{ \sqrt{2} }{2}
sin 135° = sin ( 90° + 45° ) = cos 45° =\frac{ \sqrt{2} }{2}. You can also see the graph in the attachment. 
Download docx
8 0
3 years ago
Help me plsx xndnjdsjjs
Kipish [7]
There is the answer hope it helpd if you can mark me brainliest

6 0
3 years ago
Find all values of k for which the equation 3x^2−4x+k=0 has no solutions.
dusya [7]

The given equation has no solution when K is any real number  and k>12

We have given that

3x^2−4x+k=0

△=b^2−4ac=k^2−4(3)(12)=k^2−144.

<h3>What is the condition for a solution?</h3>

If Δ=0, it has 1 real solution,

Δ<0 it has no real solution,

Δ>0 it has 2 real solutions.

We get,

Δ=k^2−144 here Δ is not zero.

It is either >0 or <0

Δ<0 it has no real solution,

Therefore the given equation has no solution when K is any real number.

To learn more about the solution visit:

brainly.com/question/1397278

5 0
2 years ago
Read 2 more answers
I NEED HELP ASAP!! WILL MAKE YOU BRAINLIEST IF RIGHT +40 points!
Simora [160]

The standard form of a quadratic equation is ,

ax² + bx + c = 0.

And the formula to find the discriminant is b² - 4ac.

Here the first step is to change the given equation into standard form. So, add 1 to each sides of the equation. Therefore,

2x² – 9x + 2+1 = –1 + 1

2x² – 9x + 3 = 0

Next step is to compare the given equation with this equation to get the value of a, b and c.

After comparing the equations we will get a = 2, b = -9 and c = 3.

So, discriminant = b²- 4ac

=( -9)²-4 (2)(3)

= 81 - 24

= 57

So, discriminant of the given equation is 57.

57 is greater than 0 and square root of 57 will result real number.

So, the correct choice is C: The discriminant is greater than 0, so there are two real roots.

8 0
3 years ago
Read 2 more answers
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