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Tema [17]
2 years ago
10

Think for a situation or application in which proportion is evident/useful

Mathematics
1 answer:
Marina CMI [18]2 years ago
8 0

Answer:

Dieting (?) since proportions of the food can affect you're diet and it's also useful to stay on track.

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Please help me out.​
grandymaker [24]

Answer:

it's 4

Step-by-step explanation:

big brainnnnnnnnnn

6 0
3 years ago
Read 2 more answers
Help! Algebra! please answer if you only know! and make it undertanding!
snow_lady [41]
1. a. Pretty much, you just have to rearrange it so that the highest power is in the front. So, here's your answer:
-6x^4+4x^2+2
b. It's a 4th-degree polynomial. A degree means that "what's the highest power?"
c. It's a trinomial. It has 3 terms, hence it's a trinomial.

2. a. Since it's an odd power and a negative coefficient, it will be:
x→∞, f(x)→-∞
x→-∞, f(x)→∞
b. The degree is even and the coefficient is negative, so it will be:
x→∞, f(x)→-∞
x→-∞, f(x)→-∞

3. a. This basically means that if you solve for x, you should get -2, 1, and 2. So, to do this, you can just write it in factored form and multiply inwards using any method of your choice (remember that in the parentheses, you should get the above value if you solve for x):
f(x) = (x-2)(x+2)(x-1)
If you multiply it out, you get (also your answer):
x^3-x^2-4x+4

4. The zeros are at x = 3, 2 and -7. Multiplicity of 3 is 1, for 2 it's 2, and for -7 it's 3.

Hope this helps!
6 0
3 years ago
Read 2 more answers
Simplify 6x•1/x^-5•x^-2
sukhopar [10]

Answer:

6x^4

Step-by-step explanation:

5 0
2 years ago
Which equation matches the graph?
Kipish [7]

Answer:

Step-by-step explanation:

we can easily find this by looking at our y intercept

our y intercept here is (0, -1) so the equation who has -1 as a constant is the one were looking for

so C would be oour answer since its the only one with -1 as its constant

hope this helps <3

8 0
3 years ago
V = 1/3 bh for b the base of the cone
ch4aika [34]

Answer:

\huge\boxed{b=\dfrac{3V}{h}}

Step-by-step explanation:

V=\dfrac{1}{3}bh\qquad\text{multiply both sides by 3}\\\\3V=3\!\!\!\!\diagup^1\cdot\dfrac{1}{3\!\!\!\!\diagup_1}bh\\\\3V=bh\qquad\text{divide both sides by}\ h\neq0\\\\\dfrac{3V}{h}=\dfrac{bh}{h}\\\\\dfrac{3V}{h}=b\to \boxed{b=\dfrac{3V}{h}}

6 0
3 years ago
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