(8x^2+5x+3)+(-5x^6-2x^5+4x^2-2x)=
8x^2+5x+3-5x^6-2x^5+4x^2-2x=
-5x^6-2x^5+(8-4)x^2+(5-2)x+3=
-5x^6-2x^5+4x^2+3x+3
Answer: Option B. -5x^6-2x^5+4x^2+3x+3
£7200
In first year depreciates by 20%, that is it is worth 80% of it's original value
80% = 
= 0.8
value after 1 year = 0.8 × £10000 = £8000
In the second year it depreciates by 10% of it's value, that is it is worth 90% of it's value at the end of the first year.
90% = 
= 0.9
value after 2 years = 0.9 × £8000 = £7200
Answer:
A is going to be 2.80
B is going to be 0.7
C points (1,0.70)
D he is buying four pounds of flour because you always put the x at the bottom and y at the top
E it will be 6.3
Step-by-step explanation:
Hope this Helped
The y intercept of this function is always (0, a).
This is because when we place 0 in for x (which is the only way it'll be on the y-axis, we get 'a' as a result. This is because of the rule that raising anything to the 0th power will result in the number 1 and multiplying anything by 1 gives us the same number. See the work below for the example.
F(x) = a*b^x
F(0) = a*b^0
F(0) = a*1
F(0) = a
And for an example with a random number, we'll use a = 5 and b = 3
F(x) = 5*3^x
F(0) = 5*3^0
F(0) = 5*1
F(0) = 5
No matter what a and b equal, the intercept will be the a value.
<h3>
Answer: Choice A. |w - q|</h3>
Let's say for example that w = 10 and q = 7. This means the distance between these values is w-q = 10-7 = 3. This is the distance between w and q.
Now let's make q larger. If w = 12 and q = 20, then w-q = 12-20 = -8 assuming we subtract in the same order. We use absolute value bars to ensure the result is positive. So instead we say
|w - q| = |12 - 20| = | -8 | = 8
Distance is never negative.
