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patriot [66]
3 years ago
10

Question 2 What is the LATERAL SURFACE AREA of this cylinder?

Mathematics
1 answer:
erastova [34]3 years ago
7 0

The lateral surface area is the area of the side thing, not the 2 circles.

If we imagine to stretch the side out, we can get a rectangle with base the circumference to the base circle, and height of 9 inches.

Therefore this area is pi*8*9=72π

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IS (3,4) a solution to y<4x-2
Ksivusya [100]

Answer:

lolololololololololololol

Step-by-step explanation:

lololololololololololol

4 0
3 years ago
Use the quadratic formula to solve the following equation -3x^2-x-3=0
tigry1 [53]

<u>Answer:</u>

x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i are two roots of equation -3 x^{2}-x-3=0

<u>Solution:</u>

Need to solve given equation using quadratic formula.

-3 x^{2}-x-3=0

General form of quadratic equation is a x^{2}+b x+c=0

And quadratic formula for getting roots of quadratic equation is

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

In our case b = -1 , a = -3 and c = -3

Calculating roots of the equation we get

\begin{array}{l}{x=\frac{-(-1) \pm \sqrt{(-1)^{2}-4(-3)(-3)}}{2 \times-3}} \\\\ {x=-\frac{1}{6} \pm\left(-\frac{\sqrt{-35}}{6}\right)}\end{array}

Since b^{2}-4 a c is equal to -35, which is less than zero, so given equation will not have real roots and have complex roots.

\begin{array}{l}{\text { Hence } x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i \text { are two roots of equation - }} \\ {3 x^{2}-x-3=0}\end{array}

8 0
4 years ago
I NEED HELP PLEASE IM STRUGGLING
zepelin [54]
I think the answer is either B or C I am not completely sure but I got 36
4 0
3 years ago
Very urgent... I need it right now.. please help me with explanation!
aliina [53]

Answer:

a) Water height, H(g) = 8g^2 + 3g -4 - [9g^2 -2g -5] = 8g^2 + 3g -4 -9g^2 + 2g +5 = -g^2 +5g +1

b) g = 1

H(g) = -(1)^2 + 5(1) + 1 = -1 + 5 + 1 = 5

g=2

H(g) = -(2)^2 + 5(2) + 1 = -4 + 10 + 1 = 7

g=3

H(g) = -(3)^2 + 5(3) + 1 = -9 +15 +1 = 5

c) Greatest height

Find the vertex of the parabole

The vertex is at the mid point between the two roots.

To find the roots you can use the quadratic equation

The result is g = 5/2 + [√29]/2 and g = 5/2 - [√29]/2

The middle poin is 5/2 = 2.5

Now find H(2.5) = -(2.5)^2 + 5(2.5) + 1 = 7.5 ≈ 7.3

hope this helps

4 0
3 years ago
1 Point
Anna007 [38]

Answer: X+5

Step-by-step explanation:

When you take out the 9 it should be 9(x+5) and when you take out the 9x on the bottom it gives you (x+5)+20 therefore x+5 is your GCF.

I hope this helps :)

5 0
3 years ago
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