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2 years ago

67cd What are the factors of the expression? Drag all of the factors of the expression into the box. Factors −1 67 6 7c d

Mathematics

1 answer:

Romashka-Z-Leto [24]2 years ago

7 0

If your looking for greatest common factors they are 1,67, c,and d.

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Day 6: Textbook Page 321 Problem 9 When Esteban looks at the puddle, he sees a reflection of the top of the cactus. How tall is

Novay_Z [31]

The given figure can be drawn as,

From the figure,

$\tan \theta=\frac{opposite\text{ side}}{\text{adjacent side}}$

$\begin{gathered} \tan \theta=\frac{DE}{EC} \\ \tan \theta=\frac{1.5}{2.5} \\ \tan \theta=0.6 \end{gathered}$

Since angle of incidence will be equal to angle of reflection, $\begin{gathered} \text{tan}$ Therefore, the height of cactus is 6 m.

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6 months ago

I need help on this question

inna [77]

Hello!

You always think of these graphs out of 100%. As you can see, the blue takes up about half of he graph. Half of 100 is 50.

Therefore, our answer is D) 50%

I hope this helps!

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2 years ago

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(-1) + (-6) + ____ = -1

Nastasia [14]

(-1)+(-6)= -7

-7 + 6 = -1

therefore, the answer is 6.

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2 years ago

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If the radioactive half-life of a substance is 20 days, and there are 5 grams of it initially. When will the amount left be 2 gr

Kobotan [32]

Answer: $26.4\ \text{days}$

Step-by-step explanation:

Given

Half life of radioactive substance is $T_{\frac{1}{2}}=20\ \text{days}$

Initial amount $A_o=2\ \text{days}$

Amount left at any time is given by

$\Rightarrow A=A_o2^{\dfrac{-t}{T_{\frac{1}{2}}}}\\\\\Rightarrow 2=52^{\dfrac{-t}{20}}\\\\\Rightarrow 0.4=2^{\dfrac{-t}{20}}\\\\\Rightarrow 2^{\dfrac{t}{20}}=2.5\\\\\Rightarrow \dfrac{t}{20}\ln 2=\ln (2.5)\\\\\Rightarrow t=\dfrac{20\ln (2.5)}{\ln 2}\\\\\Rightarrow t=26.4\ \text{days}$

It takes 26.4 days to reach 2 gm.

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2 years ago

A right triangular prism is shown. Find (A) the total surface area and (B) the volume. You must show formulas and your work.

enyata [817]

Hello!

We are going to use the rectangular prism of the image as a guide:

First of all, the AC segment is calculated using the Pythagoras' theorem:

$AC= \sqrt{ AB^{2}+ BC^{2} } =\sqrt{ 10^{2}+ 8^{2} }=12,81 m$

(A) The surface area of a prism is the sum of the surface areas of each face.

For the 2 triangles ABC and DEF

$A=2*(1/2*b*h)=2*(1/2*8m*10m)=80m$

For the ABEF Rectangle

$A=w*l=10,77m*10m=107,7m^{2}$

For the ACDE Rectangle

$A=w*l=10,77m*12,81m=137,96 m^{2}$

For the BCDF Rectangle

$A=w*l=10,77m*8m=86,16 m^{2}$

To finish you need to sum up the areas of each face:

$SA=2A_{ABC}+ A_{ABEF}+A_{ACDE}+A_{BCDF}= \\ 80 m^{2} +107,7m^{2} +137,96m^{2} +86,16m^{2} =411,82m^{2}$

(B) The volume of a prism is the product of the area of its base and the height of the prism. In this case, the base is a triangle so the formula and the calculations for the volume are as follows

$V= \frac{1}{2} *w*h*l= \frac{1}{2}* 8m*10m*10,77m=430,8m^{3}$

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3 years ago