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mariarad [96]
3 years ago
6

What I Can Do

Mathematics
1 answer:
Nostrana [21]3 years ago
8 0
The answer is 3 I’m sure because y=3
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(2,2) (6,2) (6,8) Hope this helps I’m pretty sure this is correct :)
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Factorise-              6y-15y^2<br>     HELP
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We will take the common terms in the expressions-

Here in the expression, 3y is a common term.
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Which is the value of this expression when a=5 and k=-2
Zinaida [17]

Answer:

Option C is correct.

Step-by-step explanation:

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(\frac{3^2a^{-2}}{3a^{-1}})^k

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=(\frac{3^2*5^{-2}}{3*5^{-1}})^-2\\=(\frac{3^{2-1}}{5^{-1+2}})^-2\\=(\frac{3^{1}}{5^{1}})^-2\\\\=(\frac{3}{5})^-2\\if \,\,a^{-1} \,\,then\,\, 1/a\\=\frac{(3)^{-2}}{(5)^{-2}}\\ Can\,\,be\,\,written\,\,as\\\\=\frac{(5)^{2}}{(3)^{2}} \\=\frac{25}{9}

Option C is correct.

3 0
3 years ago
Find sin theta if theta is an angle in standard position and the point with coordinates (3, -4) lies on the terminal side of an
alisha [4.7K]

Answer:

\sin \theta=-\frac{4}{5}

Step-by-step explanation:

Given:

Angle is in standard position which means the starting ray is at the origin. The terminal side has coordinates (3, -4).

So, the 'x' value is 3 and 'y' value id -4.

Using Pythagoras Theorem, we find the hypotenuse.

Hypotenuse = \sqrt{3^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5

Now, using the sine ratio for the angle, we have

\sin \theta=\frac{Opposite}{Hypotenuse}\\\sin \theta=\frac{-4}{5}\\\sin \theta=-\frac{4}{5}

Therefore, the value of \sin \theta is -\frac{4}{5}.

The value is negative as the point (3, -4) lies in the fourth quadrant and sine ratio is negative in the fourth quadrant,

4 0
3 years ago
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