Answer:
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Step-by-step explanation:
y = (x^2 - 3)^sinx
ln y = ln (x^2 - 3)^sinx
ln y = sin x * ln (x^2 - 3)
1/y * dy/dx = sin x * {1 / (x^2 - 3)} * 2x + ln(x^2 - 3) * cos x
1/y dy/dx = 2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)
dy/dx = [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)] * y
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Answer:
p
Step-by-step explanation:
Answer:
The first one is 0, the second one is ARN (All real numbers)
Step-by-step explanation:
1. Anything raised to the "zeroth" power is always 1
2. Because 7 is being raised to the zeroth power, the number inside the parentheses becomes 1. Now x can equal anything, 1 times itself will always equal 1, no matter how many times you multiply them.
