I'm assuming the limit is supposed to be
Multiply the numerator by its conjugate, and do the same with the denominator:
so that in the limit, we have
Factorize the first term in the denominator as
The terms cancel, leaving you with
and the limand is continuous at , so we can substitute it to find the limit has a value of -1/18.
Answer:
The surface of the prism is 84m²
Step-by-step explanation:
You have 4 figures here (two the same triangles)
you need to determine the surface of each and then sum it to one. This will be your final surface.
rectangles:
3*6= 18m²
5*6 = 30m²
4*6 = 24m²
triangles:
You need to determine the square of the triangles from the Heron's formula.
Heron's formula states that the area of a triangle whose sides have lengths a, b, and c is
,
where s is the semi-perimeter of the triangle; that is,
.
So the permimeter of the triangle is
2p=4+5+3 = 12m
p = 6m
So the surface of the prism is a total sum of all surfaces:
P = 18m²+30m²+ 24m²+2*6m² = 84m²