The handshake problem!
Each of the five will play against 4 others, but since A vs B can be considered the same game as B vs A, so there are 5*4/2=10 matches.
Answer:
(x+5)²(x²+5)
Step-by-step explanation:
Given two functions x²+5 and x²+10x+25, to get their Lowest common factor, we need to to first factorize x²+10x+25
On factorising we have:
x²+5x+5x+25
= x(x+5) +5(x+5
= (x+5)(x+5)
= (x+5)²
The LCM can be calculated as thus
| x²+5, (x+5)²
x+5| x²+5, (x+5)
x+5| x²+5, 1
x²+5| 1, 1
The factors of both equation are x+5 × x+5 × x²+5
The LCM will be the product of the three functions i.e
(x+5)²(x²+5)
This hives the required expression.
Answer:
The first statement is correct. only the team pitching has to make the 3 outs and once they do they switch positions
Step-by-step explanation:
the team pitching cannot score and once the batting team gets 3 outs then they switch positions, all the way until the end of the 9th inning
Step-by-step explanation:
I think it is B but I may be wrong I don't know
I think it means expires. I'm not sure though
