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alekssr [168]
3 years ago
13

Solve for x. 5(x – 10) = 30 – 15x x = 1 x = 4 x = 5 x = 8

Mathematics
2 answers:
jarptica [38.1K]3 years ago
8 0

chan eil agad ach sgrùdadh a dhèanamh air google!

5x-50 = 30-15x, 20x = 80, x = 4,

x=4!

-BARSIC- [3]3 years ago
8 0

Answer:

x=4

Step-by-step explanation:

5x-50 = 30-15x, 20x = 80, x = 4,

x=4

hope this helps

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The variable z is directly proportional to x. When x is 10, z has the value 140.
gayaneshka [121]

Answer: z = 280

Step-by-step explanation:

If two variables are directly proportional, it means that an increase in the value of one variable causes an increase in the value of the other variable. Also, a decrease in the value of one variable causes an decrease in the value of the other variable.

The variable z is directly proportional to x. If we introduce a constant of variation, the expression would be

z = kx

When x is 10, z has the value 140. It means that

140 = 10k

k = 140/10

k = 14

The equation becomes

z = 14x

the value of z when x = 20 is

z = 14 × 20

z = 280

7 0
3 years ago
Help with number 7 !!!
FrozenT [24]

A is the correct answer i think

3 0
2 years ago
g A sample of 3 items is chosen at random from a box containing 20 items, out of which 4 are defective. Let X be the number of d
professor190 [17]

Answer:

The variance and standard deviation of <em>X</em> are 0.48 and 0.693 respectively.

The variance and standard deviation of (20 - <em>X</em>) are 0.48 and 0.693 respectively.

Step-by-step explanation:

The variable <em>X</em> is defined as, <em>X</em> = number of defective items in the sample.

In a sample of 20 items there are 4 defective items.

The probability of selecting a defective item is:

P (X)=\frac{4}{20}=0.20

A random sample of <em>n</em> = 3 items are selected at random.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 3 and <em>p </em>= 0.20.

The variance of a Binomial distribution is:

V(X)=np(1-p)

Compute the variance of <em>X</em> as follows:

V(X)=np(1-p)=3\times0.20\times(1-0.20)=0.48

Compute the standard deviation (σ (X)) as follows:

\sigma (X)=\sqrt{V(X)}=\sqrt{0.48}=0.693

Thus, the variance and standard deviation of <em>X</em> are 0.48 and 0.693 respectively.

Now compute the variance of (20 - X) as follows:

V(20-X)=V(20)+V(X)-2Cov(20,X)=0+0.48-0=0.48

Compute the standard deviation of (20 - X) as follows:

\sigma (20-X)=\sqrt{V(20-X)} =\sqrt{0.48}0.693

Thus, the variance and standard deviation of (20 - <em>X</em>) are 0.48 and 0.693 respectively.

3 0
2 years ago
How do you find the normal approximation without using the continuity correction?
Dennis_Churaev [7]
Let's say you want to compute the probability \mathbb P(a\le X\le b) where X converges in distribution to Y, and Y follows a normal distribution. The normal approximation (without the continuity correction) basically involves choosing Y such that its mean and variance are the same as those for X.

Example: If X is binomially distributed with n=100 and p=0.1, then X has mean np=10 and variance np(1-p)=9. So you can approximate a probability in terms of X with a probability in terms of Y:

\mathbb P(a\le X\le b)\approx\mathbb P(a\le Y\le b)=\mathbb P\left(\dfrac{a-10}3\le\dfrac{Y-10}3\le\dfrac{b-10}3\right)=\mathbb P(a^*\le Z\le b^*)

where Z follows the standard normal distribution.
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3 years ago
How do you multiple fractions
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Fractions they are easy REALLY!!

5 0
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