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olasank [31]
3 years ago
12

How do I solve the running time of a train between two terminals is 48 minutes, and there is a 7-minutes layover at each termina

l. If a train leaves one terminal at 11:00 a.m. This train is due back at the same terminal at what time??
Mathematics
1 answer:
bagirrra123 [75]3 years ago
5 0
At First lets say the train is at terminal A
To get to terminal B ( next terminal )
It takes him 48 minutes
Then spend 7 more minutes at terminal B
( 48 + 7 = 55 minutes spent so far )

Then spend 48 more minutes from terminal B to go back to terminal A
( 55+ 48 = 103 minutes spent)

Convert minute to hour ( divide by 60 )

103/60 = 1.7 h

11 + 1.7 = 12.7
So the time would be 7 minutes past 12
12:07 pm.
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5 0
3 years ago
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Angle ABD and angle DBC are linear pairs, and angle ABD and angle EDC are vertical angles. If the measure of angle ABD=5(2x+1),
Ugo [173]
∠ ABD = 5(2X+1)
∠ DBC = 3X+6
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∠ ABD and ∠ DBC are linear pairs
∴ ∠ ABD +∠ DBC = 180
∴ 5(2X+1) + 3X+6 =180
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∴∠ ABD = 5(2X+1) = 5(2*13+1) = 135
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∠ ABD  and ∠ EBC are vertical angles
∴ ∠ ABD = ∠ EBC = 135
∴ y +135/2 = 135
∴ y = 135/2

The <span>statements that are true:
--------------------------------------</span><span>
C.) x=13
E.)measure of angle EBC =135
F.) angle DBC and angle EBC are linear pairs </span>




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