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solong [7]
3 years ago
11

Snow is falling steadily in Syracuse, New York. After 2 hours, 4 inches of snow has fallen. Use the table to help you answer the

questions below.
Mathematics
1 answer:
Olegator [25]3 years ago
3 0

Answer:

every one hour it's two inches of snow

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What does 1694 quarter hours convert to in hours?
tino4ka555 [31]
1694/4 = 423,5
Answer: 423,5 hours.
8 0
3 years ago
A girl 160cm tall, stands 360 cm from a lamp post at night. Her shadow from the light is 90 cm long. How high is the lamp post?
Volgvan
The lamp post is 202.5 cm high. 

Hope this answer helped..it would really help me if you gave me brainliest answer, I desperately need. Thanks
3 0
3 years ago
Do the information on a bag of fertilizer 5 pounds of fertilizer are needed for every two square feet of lawn how many square fe
gregori [183]

Answer:

25 lb bag of fertilizer can cover <u>10 square feet</u> of lawn.

Step-by-step explanation:

Given:

5 pounds of fertilizer cover = 2 ft^2 of the lawn

We need to find the 25 lb bag cover.

Solution:

Now we know that;

5 pounds of fertilizer = 2  ft^2 of yard.

1 lb of fertilizer = Number of ft^2 lawn covered by 1 lb fertilizer.

Using Unitary method we get;

Number of ft^2 lawn covered by 1 lb fertilizer = \frac{2}{5}\ ft^2

Now we can say that;

1 lb of fertilizer =  \frac{2}{5}\ ft^2 of the yard

25 lb of fertilizer = Number of ft^2 lawn covered by 25 lb fertilizer.

Again by using Unitary method we get;

Number of ft^2 lawn covered by 25 lb fertilizer. = \frac{2}{5}\times 25 = 10 \ ft^2

Hence 25 lb bag of fertilizer can cover <u>10 square feet</u> of lawn.

7 0
3 years ago
Let C(x) be the statement "x has a cat," let D(x) be the statement "x has a dog," and let F(x) be the statement "x has a ferret.
jek_recluse [69]

Answer:

\mathbf{a)} \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\\\mathbf{b)} \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee \; F(x)\\\mathbf{c)} \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)\\\mathbf{d)} \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)\\\mathbf{e)} \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

Step-by-step explanation:

Let X be a set of all students in your class. The set X is the domain. Denote

                                        C(x) -  ' \text{$x $ has a cat}'\\D(x) -  ' \text{$x$ has a dog}'\\F(x) -  ' \text{$x$ has a ferret}'

\mathbf{a)}

Consider the statement '<em>A student in your class has a cat, a dog, and a ferret</em>'. This means that \exists x \in X so that all three statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                         \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)

\mathbf{b)}

Consider the statement '<em>All students in your class have a cat, a dog, or a ferret.' </em>This means that \forall x \in X at least one of the statements C(x), D(x) and F(x) is true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                        \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee F(x)

\mathbf{c)}

Consider the statement '<em>Some student in your class has a cat and a ferret, but not a dog.' </em>This means that \exists x \in X so that the statements C(x), F(x) are true and the negation of the statement D(x) . We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                      \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)

\mathbf{d)}

Consider the statement '<em>No student in your class has a cat, a dog, and a ferret..' </em>This means that \forall x \in X none of  the statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as a negation of the statement in the part a), as follows

\neg \left( \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\right) \iff \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)

\mathbf{e)}

Consider the statement '<em> For each of the three animals, cats, dogs, and ferrets, there is a student in your class who has this animal as a pet.' </em>

This means that for each of the statements C, F and D there is an element from the domain X so that each statement holds true.

We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

           \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

5 0
4 years ago
Gerardo compró un servicio de limpieza para su negocio que le cobra $300 por cada uno de los dos primeros servicios y $150 por s
andrey2020 [161]

Answer:

CT= $950

Step-by-step explanation:

Dado la siguiente información:

Servicio= $300 primeros dos

Servicio adicional= $150

Descuento= $100

<u>Para calculate el costo total, tenemos que usar la siguiente formula:</u>

CT= 300x + 150y - 100

x= costo normal

y= costo promocional

CT= 300*2 + 150*3 - 100

CT= $950

4 0
3 years ago
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