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WITCHER [35]
2 years ago
6

? x 10 = 6,026.1 what would be the first number

Mathematics
2 answers:
Nadusha1986 [10]2 years ago
7 0

Answer:

602.61

Step-by-step explanation:

me big brain

poizon [28]2 years ago
6 0

Answer:

602.61

Step-by-step explanation:

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The length of a rectangle is four times its width.
mixer [17]

Let width be x

  • length=4x

ATQ

\\ \sf\longmapsto 2(x+4x)=70

\\ \sf\longmapsto 5x=35

\\ \sf\longmapsto x=7

  • Width=7ft
  • Length=7(4)=28ft
3 0
2 years ago
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What is the cost of the TV?
sasho [114]
20%of £800 is 800÷5 =160
800 + 160 =960
6 0
3 years ago
Rihanna has 5 less than 2 times as many homework problems to complete as her friend Terrika. The total number of homework proble
wariber [46]

Answer: 19=5x times 2

Step-by-step explanation:

5 0
2 years ago
At a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective pa
11Alexandr11 [23.1K]

Answer:

Probability that fewer than 2 of these parts are defective is 0.604.

Step-by-step explanation:

We are given that at a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective parts 19% of the time.

A random sample of 7 parts produced by this machine is chosen.

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 7 parts

            r = number of success = fewer than 2

           p = probability of success which in our question is % of defective

                 parts produced by one of the machine, i.e; 19%

<em>LET X = Number of parts that are defective</em>

<u>So, it means X ~ Binom(n = 7, p = 0.19)</u>

Now, probability that fewer than 2 of these parts are defective is given by = P(X < 2)

    P(X < 2) = P(X = 0) + P(X = 1)

                  =  \binom{7}{0}\times 0.19^{0} \times (1-0.19)^{7-0}+ \binom{7}{1}\times 0.19^{1} \times (1-0.19)^{7-1}

                  =  1 \times 1 \times 0.81^{7} +7 \times 01.9^{1} \times 0.81^{6}

                  =  <u>0.604</u>

<em>Therefore, the probability that fewer than 2 of these parts are defective is 0.604.</em>

8 0
2 years ago
Cara has $25 to buy dry pet food a pound of dog food costs $2 and treats are $1 apiece if she buys 9 pounds of food the greatest
zzz [600]

Cost of each pound of dog food = $2 .

Total cost of 9 pounds of dog food = 9 * 2 = $18.

Let us assume number of treats she can buy = t.

Cost of each treat = $1.

Cost of t number of treats = 1*t = 1t .

Total money Cara has = $25.

We can setup an inequality as,

Total cost of dog food + total cost of t number of treats ≤ 25.

18 + 1t ≤ 25.

Subtracting 18 from both sides, we get

18 + 1t -18  ≤ 25-18.

1t ≤ 7 or t ≤ 7.

So, she can purchase 7 or less treats.

5 0
2 years ago
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