After rotating a point C 90° counterclockwise about the origin the coordinates of C' would be (-2, 1)
In this question, we have been given a triangle ABC.
A point C is at (1, 2)
The triangle is rotated counter clockwise 90° about the origin.
We need to find the coordinates of C' which is image of vertex C after rotation.
We know that, if we rotate a point 90° counterclockwise about the origin a point (x, y) becomes (-y, x).
Here C(1, 2) is rotated 90 degrees counterclockwise about the origin.
So, the coordinates of C' would be,
C' = (-2, 1)
Therefore, after rotating a point C 90° counterclockwise about the origin the coordinates of C' are (-2, 1)
Learn more about the rotation here:
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Answer:
True both are 28/15
Step-by-step explanation:
Simplify the following:
5 + 2/3 - (3 + 4/5)
Put 3 + 4/5 over the common denominator 5. 3 + 4/5 = (5×3)/5 + 4/5:
5 + 2/3 - (5×3)/5 + 4/5
5×3 = 15:
5 + 2/3 - (15/5 + 4/5)
15/5 + 4/5 = (15 + 4)/5:
5 + 2/3 - (15 + 4)/5
15 + 4 = 19:
5 + 2/3 - 19/5
Put 5 + 2/3 - 19/5 over the common denominator 15. 5 + 2/3 - 19/5 = (15×5)/15 + (5×2)/15 + (3 (-19))/15:
(15×5)/15 + (5×2)/15 + (3 (-19))/15
15×5 = 75:
75/15 + (5×2)/15 + (3 (-19))/15
5×2 = 10:
75/15 + 10/15 + (3 (-19))/15
3 (-19) = -57:
75/15 + 10/15 + (-57)/15
75/15 + 10/15 - 57/15 = (75 + 10 - 57)/15:
(75 + 10 - 57)/15
| 7 | 5
+ | 1 | 0
| 8 | 5:
(85 - 57)/15
| 7 | 15
| 8 | 5
- | 5 | 7
| 2 | 8:
Answer: 28/15
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Simplify the following:
1 + 13/15
Put 1 + 13/15 over the common denominator 15. 1 + 13/15 = 15/15 + 13/15:
15/15 + 13/15
15/15 + 13/15 = (15 + 13)/15:
(15 + 13)/15
| 1 | 5
+ | 1 | 3
| 2 | 8:
Answer: 28/15
Numbers divisible by 5 from 2 to 50 is 10 and numbers divisible by 8 from 2 to 50 is 6 ,therefore 6+ 10 =16 making 16/50 =8/25
Step-by-step explanation:
We can use the formula to find the number of moles. As ,
n = No. of particles/ N_A
n = 3.01× 10¹⁸/6.022 × 10²³
n = 1/2 / 10⁵
<h3>Hence the number of particles is 1/2 / 10⁵ </h3>
The answer:
X1 = -1 X2 = 3
Explanation: Down the images
